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3 years ago

When must a psychological researcher debrief human test subjects?

1 answer:

3 0

<span>Psychological researchers must debrief human test subjects </span><span>at the end of every experiment.

The current code of ethics in p</span>sychological research states that researchers absolutely must debrief human test subjects at the end of every study regardless or whether or not harm or deception was involved.

Debriefing a subject after a study is an essential opportunity for the researcher to explain the purpose and aim of the study to the subject, make sure the subject is not harmed or mentally disturbed, clarify why deception was used (if deception was involved) and overall, to clarify any questions or doubts the subject might have.

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A positive force on the balance indicates a downward force on the silver sphere while a negative force on the balance indicates

anastassius [24]

The two spheres have opposite charges.

<h3 /><h3 /><h3>What are types charge?</h3>

A charge can be negatively charged or positively charged.

When two charges have opposite signs, that is positive and negative signs, the two charges will attract each other.
When the two charges have the same sign, it causes repulsion.

When a positive charge points downwards ↓ and the negative charge points upwards ↑, this causes attraction and shows that the two charges are different.

Thus, we can conclude that the two spheres have opposite charges.

Learn more about attraction and repulsion of charges here: brainly.com/question/2396080

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2 years ago

The measurement of an exoplanet's radius is measured in units compared to ________.

sesenic [268]

The eaths radius is the correct answer, if you need proof look at nasa's website

4 0

3 years ago

Read 2 more answers

What is the total energy of a particle with a rest mass of 1 gram moving with half the speed of light? 1 eV = 1.6 x 10^-19 J. An

GREYUIT [131]

Answer:

6.5 x 10^32 eV

Explanation:

mass of particle, mo = 1 g = 0.001 kg

velocity of particle, v = half of velocity of light = c / 2

c = 3 x 10^8 m/s

Energy associated to the particle

E = γ mo c^2

$E=\frac{m_{0}c^}2}{\sqrt{1-\frac{v^{2}}{c^{2}}}}$

$E=\frac{m_{0}c^}2}{\sqrt{1-\frac{c^{2}}{4c^{2}}}}$

$E=\frac{2m_{0}c^}2}{\sqrt{3}}$

$E=\frac{2\times0.001\times9\times10^{16}}{1.732}$

$E=1.04\times10^{14}J$

Convert Joule into eV

1 eV = 1.6 x 10^-19 J

So, $E=\frac{1.04\times10^{14}}{1.6\times10^{-19}}=6.5\times10^{32}eV$

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3 years ago

8. A car moved 20 km East and 70 km West.<br> What is the distance?

SCORPION-xisa [38]

Your answer is.......a car moved 60 km East and 90 km in west.

7 0

3 years ago

Read 2 more answers

Please help me with the equations for this! Three uniform spheres are fixed at the positions shown in the diagram. ( there is a

lora16 [44]

The change in gravitational potential energy due to change in position must be the change in it's kinetic energy as the system is isolated! so find out the potential energies of the two different points!

<span>PE=−[G<span>M1</span><span>M2</span>]÷R

</span><span> Potential energy of a particle due to mass A is not affected by presence of any other mass B !</span>

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3 years ago