Answer:
it is A mark me big brain pls
Explanation:
Answer:17.65g
Explanation:
Use ratio and calculate from the balanced equation
Answer:
Volume of acetone = 257.4 mL
Explanation:
Density = mass / volume
Density Hg = Mass Hg / Volume Hg
13.59 g/mL = Mass Hg / 15 mL Hg
13.59 g/mL . 15 mL = Mass Hg → 203.85 g
This is the mass of acetone
Density acetone = Mass acetone / Volume acetone
0.792 g/mL = 203.85 g / Volume of acetone
Volume of acetone = 203.85 g / 0.792 g/mL
Volume of acetone = 257.4 mL
D. Both B and C because the speed doesn’t really matter it is what it might cause
The volume (in mL) of the 1.00 M LiOH needed to prepare 500.00 mL of 0.075 M of LiOH is 37.5 mL
<h3>How do I determine the volume (in mL) of LiOH needed?</h3>
Dilution formula is given as follow:
M₁V₁ = M₂V₂
Where
- M₁ is the molarity of stock solution
- V₁ is the volume of stock solution
- M₂ is the molarity of diluted solution
- V₂ is the volume of diluted solution
Applying the above formula, we obtain the volume (in mL) of LiOH needed to prepare 500.00 mL of 0.075 M of LiOH. This is illustrated below:
- Molarity of stock solution of LiOH (M₁) = 1.00 M
- Volume of diluted solution of LiOH (V₂) = 500.00 mL
- Molarity of diluted solution of LiOH (M₂) = 0.075 M
- Volume of stock solution of LiOH needed (V₁) =?
M₁V₁ = M₂V₂
1 × V₁ = 0.075 × 500
V₁ = 37.5 mL
Thus, the volume (in mL) of LiOH needed is 37.5 mL
Learn more about volume:
brainly.com/question/24159217
#SPJ1
