Question

How many atoms are contained in 10.0 g of silver?

Answer 1

Answer:

5.418 ×10^22

or 5.42 ×10^22

Explanation:

$1 \: mol \: of \: ag = 107g \\ \ x \: mol \: of \: ag \: = 10g \\ so \: 10 \div 107 = 0.09 \\ x = 0.09mol \\ \\ \\ so \: 1mol = 6.02 \times {10}^{23} \\ 0.09mol = x \: molecules \\ \\ 0.09 \times 6.02 \times 10 ^{23} \\ = 5.42 \times {10}^{22}$

$0.09 \times 6.02 \times {10}^{23} \\ = 5.418 \times {10}^{22} molecules$