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Marina CMI [18]
2 years ago
13

A ball falls off of a 3m tall shelf. How long will it take for the

Physics
1 answer:
natali 33 [55]2 years ago
7 0

Answer:

0.8s

Explanation:

Given parameters:

Height of shelf  = 3m

Unknown:

Time it will take to hit the ground  = ?

Solution:

To solve this problem, we use the expression below;

         x  = ut + \frac{1}{2} gt²  

x is the height

u is the initial velocity  = 0m/s

g is the acceleration due to gravity  = 9.8m/s²

t is the time taken  = ?

Now insert the parameters and solve for t;

    3  = (0 x t) +( \frac{1}{2} x 9.8 x t²)

    3 = 4.9t²

       t² = 0.6

       t = 0.8s

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3 years ago
A ball is thrown vertically upwards with a velocity
zhuklara [117]

Answer:

Explanation:

The acceleration of gravity is 9.8m/s^2.

So to calculate the time it will take to make the ball stop(which btw means the ball now reach its greatest height), use the formula V1=V0+at. V1 is the final velocity(which is 0), V0 is the starting velocity(which is 30m/s), and the a(cceleration) is 9.8m/s^2.

(You can ignore the fact "at" is -30 instead 30, it's because the directions two velocity travel are opposite. )

We can now know the time it takes to make the ball stop just by the gravitational force is about 3 sec.

Use another formula S=1/2at^2, to find out the S(height) is 1/2*9.8*3^2=44.1, which is approximately D.45m .

6 0
2 years ago
The driver of a car traveling at 22.8 m/s applies the brakes and undergoes a constant deceleration of 2.95 m/s 2 . How many revo
a_sh-v [17]

Answer:

70 revolutions

Explanation:

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t = \Delta v/a = (22.8 - 0)/2.95 = 7.73 s

The tire angular velocity before stopping is:

\omega_0 = v/r = 22.8 / 0.2 = 114 rad/s

Also its angular decceleration:

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Using the following equation motion we can findout the angle it makes during the deceleration:

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

where \omega = 0 m/s is the final angular velocity of the car when it stops, \omega_0 = 114rad/s is the initial angular velocity of the car \alpha = 14.75 rad/s2 is the deceleration of the can, and \Delta \theta is the angular distance traveled, which we care looking for:

-114^2 = 2*(-14.75)*\Delta \theta

\Delta \theta = 440rad or 440/2π = 70 revelutions

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2 years ago
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Answer:

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