Answer:
yes it does exert a force, it pushes it up
Explanation:
this is called normal force
if it didn't exert a force the book would keep going down
according to newton every force has an equal amd opposite reaction
so the book exerts a force on the table and vice versa
hope this helped
Answer:
23. Option B. Hertz
29. Refraction.
Explanation:
23. Determination of the unit of measurement of frequency.
Frequency is simply defined as the number of oscillation made in one second. Mathematically, frequency can be represented as:
Frequency = 1/period
f = 1/T
Period is measured in seconds.
Thus, the unit of frequency becomes
f = 1/T
f = 1/s = s¯¹ (Hertz)
Therefore, the unit of frequency is Hertz.
29. When a wave enters a new medium, the speed of the wave is uttered. This leads to the bending of the wave. When this occurs, we can say refraction has taken place.
Chameleon tongue reaches 23 cm.
Train's final speed is 32 m/s.
The distance the tongue travels is divided into 2 phases.
1. The acceleration phase.
2. The coasting phase.
For the acceleration phase, the formula d = 0.5AT^2 determines how far the tongue travels while accelerating. The during the coasting phase, the tongue continues onward without changing its velocity, so it's formula is d = VT. The peak velocity of the tongue will be reached after 20 ms. So let's calculate it.
d = 0.5AT^2
d = 0.5*290 m/s^2 * (0.020 s)^2
d = 145 m/s^2 * 0.0004 s^2
d = 0.058 m
Now to handle coasting
d = 0.058 m + 0.030 s * 290 m/s^2 * 0.20 s
d = 0.058 m + 0.174 m
d = 0.232 m
Rounding to 2 significant digits gives 0.23 meters, or 23 cm.
For the train, we need to determine the acceleration. We know the velocity changed from 5.0 m/s to 14.0 m/s over a period of 8.0 seconds. So the acceleration is:
(14.0 m/s - 5.0 m/s)/8.0 s = (9.0 m/s)/8.0 s = 1.125 m/s^2
At the edge of town, the train is traveling at 14 m/s and accelerates at 1.125 m/s^2 for 16 seconds, so:
14 m/s + 1.125 m/s^2 * 16 s = 14 m/s + 18 m/s = 32 m/s
So the final speed of the train is 32 m/s
Answer:
t = 94.91 nm
Explanation:
given,
wavelength of the light = 522 nm
refractive index of the material = 1.375
we know the equation
c = ν λ
where ν is the frequency of the wave
c is the speed of light
ν = 5.75 x 10¹⁴ Hz
the thickness of the coating will be calculated using
t = 94.91 nm
the thickness of the coating will be equal to t = 94.91 nm