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nevsk [136]
3 years ago
14

A straight railroad track is being built to connect two cities. the measured distance of the track between the two cities is 160

.5 miles. a mailstop is 28.5 miles from the first city. how far is the mailstop from the second city?
Physics
1 answer:
elena55 [62]3 years ago
7 0
Let point A be 0.0 miles (first city)
Let point B be 160.5 miles (first city to second city)
Let point C be 28.5 miles (first city to mail stop)

Take C – A = C [28.5 - 0.0 = 28.5] (This checks the distance between city 1 and Mail stop) 

Then Take B – C = Distance from the first city to the second city [160.5 - 28.5 = 132 Miles]


Answer: The Mail stop is 132 miles from the Second City.
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The problem corresponds to the motion of a projectile (the salmon), with initial speed v_0, initial direction \theta=37.6^{\circ} and vertical acceleration g=9.81 m/s^2 downward. The two equations which gives the horizontal and vertical position of the salmon at time t are

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A system of two objects has ΔKtot = 6 J and ΔUint = -5 J. Part A How much work is done by interaction forces? Express your answe
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A) +5 J

B) +1 J

Explanation:

A)

The internal forces (interaction forces) acting on a system do not change the mechanical energy (sum of potential and kinetic energy) of the system.

However, these forces are responsible for converting the energy from one form into another; the work done by these forces is equal to the amount of energy converted from one form into the other.

In this problem, we have:

\Delta U=-5 J is the loss in potential energy of the system

\Delta K=+6 J is the gain in kinetic energy of the system

By looking at these numbers, this means that the internal forces have converted 5 J of energy from potential energy into kinetic energy (while the additional +1 J missing is due to external forces, as explained in part B).

Therefore, the work done by internal forces is

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B)

First of all, we calculate the change in mechanical energy of the system.

The mechanical energy of a system is the sum of its kinetic energy (K) and its potential energy (U):

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So, the change in mechanical energy is equal to the sum of the changes of kinetic energy and the changes of potential energy:

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In this problem:

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So, the change in mechanical energy is:

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According to the work-energy theorem, the work done by external forces on a system is equal to the change in mechanical energy of the system: therefore in this case, the work done by external forces is

W=\Delta E=+1 J

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