Your question isn't quite clear, but if you're wondering if a chemical is polar or non-polar, you simply draw a VSEPR sketch and draw arrows where the bonds are. Only draw arrows between atoms, NOT between an atom and a lone pair of electrons. The arrow should point to the most electronegative atom (you should be given an electronegativity scale). Afterwards, you add up the arrows as vectors, and look at the sum of the vectors. If the sum is zero (CH4 is a good example), the chemical is non-polar. If the sum is a vector, the chemical is polar (H2O, or water, is polar).
Answer:
water
water is the worlds best solvent cause it can melt many different things also it is called the "Universal Solvent"
<span>purples wavelength is about 400 nano meters while green's wavelength is about 540 nano meters</span>
Answer:
The enthalpy of the reaction is -2855.622 kilo Joules.
Explanation:

We are given:




The equation used to calculate enthalpy of reaction :
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28reactant%29%5D)
The equation for the enthalpy change of the above reaction is:

Putting values in above equation, we get:
![\Delta H^o_{rxn}=[4 mol\times (-393.5 kJ/mol)+6 mol\times (-241.826 kJ/mol)]-[2 mol\times (-84.667 kJ/mol)+7 mol\times 0 kJ/mol]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B4%20mol%5Ctimes%20%28-393.5%20kJ%2Fmol%29%2B6%20mol%5Ctimes%20%28-241.826%20kJ%2Fmol%29%5D-%5B2%20mol%5Ctimes%20%28-84.667%20kJ%2Fmol%29%2B7%20mol%5Ctimes%200%20kJ%2Fmol%5D)

The enthalpy of the reaction is -2855.622 kilo Joules.
Ans: (D) 0
Hope my answer is correct:))