The Change in Gibb's free energy, ΔG for the reaction at 298K is; -56.92KJ.
<h3>Gibb's free energy of reactions</h3>
It follows from the Gibb's free energy formula as expressed in terms of Enthalpy and Entropy that;
On this note, it follows that;
Hence, the Gibb's free energy for the reaction is;
- ΔG = 14.6 - 71.52
- ΔG = -56.92KJ
Remarks: The question requires that we determine the Gibb's free energy for the reaction at 298K.
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brainly.com/question/13765848
The word that is in an incorrect place in the chart is HAIL.
The state of matter of hail is not plasma; hail is a solid at room temperature. Plasma refers to the state of matter in which an ionized gas have approximately equal number of positively and negatively charged ions. Thus, plasma is an ionized gas. Plasma is considered to be the fourth state of matter. <span />
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
To calculate the amount of heat absorbed or released, we use the following equation:
.....(1)
where, q = amount of heat absorbed or released.
m = mass of the substance
c = heat capacity of water = 4.186 J/g ° C
= Change in temperature
We are given:
Putting values in equation 1, we get:
q = 5023.2 J
We are given:
Putting values in equation 1, we get:
q = 1674.4 J
Heat gained by Trial 1 than trial 2 =
Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.
Thus, the correct answer is Option b.