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Lady bird [3.3K]
3 years ago
12

How many hydrogen atoms are in 5 molecules of isopropyl alcohol, c3h7o?

Chemistry
2 answers:
Oduvanchick [21]3 years ago
7 0
1 molecule of C3H7O has 7 atoms of hydrogen (remember that the numbers to the right of each symbol ara subscripts and they indicate the number of atoms of that element in the molecular formula).

Then 5 molecules will have 5 * 7 atoms of hydrogen.

5 * 7 = 35.

Then the answer is that there are 35 atoms of hydrogen in 5 molecules of isopropyl alcohol, C3H7O
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

5 molecules will have 5 * 7 atoms of hydrogen.

5 * 7 = 35.

Explanation:

Then the answer is that there are 35 atoms of hydrogen in 5 molecules of isopropyl alcohol, C3H7O

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Which statement describes the masses of the particles that make up an atom?
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Expand in powers. use the decimal values of any digits unique to the hexadecimal system.
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Expanding in powers 4FCsixteen.

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1 year ago
When butane burns completely, only water and carbon dioxide gas are produced. If 11.6 g of butane and 40.0 L of oxygen at 22.0o
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19.7 litre volume of carbon dioxide gas at 22.0o C and 102 kPa can be collected over water.

<h3>What is vapour pressure?</h3>

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

Moles of Butane = mass in grams / molar mass = 11.6 / 58.12 = 0.2

Volume of O_2 (V) = 40 liter

Temperature (T) = 22°C = 22 + 273 = 295 K

Pressure (P) = 102 kPa = 102 / 101.325 = 1.007 atm

Moles of O_2 (n) can be calculated by ideal gas equation.

PV = nRT

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Balanced chemical reaction;

2C_4H_10 + 13O_2 ---> 8CO_2 + 10H_2O

From reaction;

13 moles O_2 require 2 moles C_4H_10

So, 1.663 moles O_2 will require = 2 x 1.663 ÷13 = 0.256 moles of C_4H_10

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Applying the ideal gas equation for CO_2,

PV = nRT

0.985 V = 0.8 0.0821 x 295

V = 19.7 liter

The volume of CO_2 produced = 19.7 liter.

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Answer:

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