It a because I learn it in class today
The answer is option C) The car experienced negative acceleration with velocity in the positive direction.
Answer:
ω = 10.75 rad/s
Explanation:
The stone leaves the circular path with a horizontal speed
v₀ = vt = R*ω
So
ω = v₀ / R
we are given that R = x / 25.7 so ω = 25.7*v₀ / x
Kinematics gives x = v₀*t
With this substitution for x the expression for ω becomes ω = 25.7 / t
Kinematics also gives for the vertical displacement y that
y = v₀y*t + 0.5*ay*t²
we know that v₀y = 0 m/s
since the stone is launched horizontally, so that
y = 0.5*ay*t² ⇒ t = √(2*y / ay)
Using this result for t in the expression for ω and assuming that upward is positive, we get
ω = 25.7 / √(2*y / ay)
⇒ ω = 25.7 / √(2*(-28) / (-9.8))
⇒ ω = 10.75 rad/s
Answer:
Explanation:
Radius of the charged sphere (R)=12cm
Charge (q)=6∗10^−6C
Electric field intensity (E)=?
i) On the surface
ii) Inside the sphere,
E=0; Because charge enclosed by Gaussian surface is zero.
iii) Outside the sphere at distance 15cm
i.e. r=12+15=27cm=0.27m
