Answer: 116 g of copper
Explanation:
![Q=I\times t](https://tex.z-dn.net/?f=Q%3DI%5Ctimes%20t)
where Q= quantity of electricity in coloumbs
I = current in amperes = 24.5A
t= time in seconds = 4.00 hr =
(1hr=3600s)
![Q=24.5A\times 14400s=352800C](https://tex.z-dn.net/?f=Q%3D24.5A%5Ctimes%2014400s%3D352800C)
of electricity deposits 63.5 g of copper.
352800 C of electricity deposits =
of copper.
Thus 116 g of Cu(s) is electroplated by running 24.5A of current
Thus remaining in solution = (0.1-0.003)=0.097moles
Answer:
3.01 × 10^24 particles
Explanation:
According to Avagadro, in one mole of a substance, there are 6.02 × 10^23 atoms or particles.
Using the formula: N = n × NA
Where;
N= number of particles or atoms
n = number of moles
NA = Avagadro's constant or number
This means that for 5 moles of a substance, there will be:
5 × 6.02 × 10^23
= 30.1 × 10^23
= 3.01 × 10^24 particles
All of the boxes in the chart are Gg
1. 100%
2. 0%