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3 years ago

I need help with this

Physics

1 answer:

mojhsa [17]3 years ago

7 0

Answer:

1) distance walked = 210 m

2) not sure

3) avg speed = total d/ total t = 210/52 = 4 m/s approx

4) For avg vel, use the formula - displacement/time

Explanation:

im not fully sure but i studied this last year

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You can answer this to get points its not an actual question

larisa86 [58]

Answer:

the electromagnetic pulse

Explanation:

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3 years ago

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What is happening to the velocity of an object if it has a negative acceleration?

oksano4ka [1.4K]

Answer:

<h3>According to our principle, when an object is slowing down, the acceleration is in the opposite direction as the velocity. Thus, this object has a negative acceleration. In Example D,<u> the object is moving in the negative direction</u> (i.e., has a negative velocity) and is speeding up.</h3>

Explanation:

So it would be decreasing if its moving towards the negative!

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3 years ago

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2. Using Graph 2, calculate the net force experienced by the particle between 4 and 6 seconds. The

Trava [24]

Using Newtons Second Law:

F = m×a

F = (0.25 kg)(-2 m/s²)

F = -0.5 N

<h2>The correct option is C</h2>

3 0

3 years ago

By what factor is the intensity of sound at a rock concert louder than that of a whisper when the two intensity levels are 120 d

77julia77 [94]

Answer:

The intensity of sound at rock concert is 10¹⁰ greater than that of a whisper.

Explanation:

The intensity of sound is given by;

$I(dB) = 10Log(\frac{I}{I_o} )$

where;

I is the intensity of the sound

I₀ is the threshold of sound intensity = 1 x 10⁻¹² W/m²

The intensity of sound at a rock concert

$120 = 10Log(\frac{I}{1*10^{-12}} )\\\\12 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{12}\\\\I = 1*10^{-12} *10^{12}\\\\I = 1*10^0\\\\I =1 \ W/m^2$

The intensity of sound of a whisper

$20 = 10Log(\frac{I}{1*10^{-12}} )\\\\2 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{2}\\\\I = 1*10^{-12} *10^{2}\\\\I = 1*10^{-10}\\\\I =10^{-10} \ W/m^2$

Thus, the intensity of sound at rock concert is 10¹⁰ greater than that of a whisper.

4 0

3 years ago

A Porsche challenges a Honda to a 400 m race. Because the Porsche’s acceleration is 3.50 m/s2 is larger than the Honda’s 3.00 m/

Talja [164]

Answer:

There are a couple of ways to do this.

(i) Set up the two kinematics equations:

Honda: s = ½at² = ½ * 3m/s² * t² = 1.5m/s² * t²

Porsche: S = ½ * 3.5m/s² * (t - 1s)² = 1.75m/s² * (t - 1s)²

When does s = S ? Dropping units for ease,

1.5t² = 1.75(t-1)²

which is quadratic and has solutions at t = 0.5 s → which is no good, since it would leave the porsche with -0.5 s, which isn't possible, and

t = 13.5 s

When they've gone the same distance, they've gone

d = 1.5m/s² * (13.5s)² = 273 meters

The Porsche wins easily. ◄

Want to make it interesting? Give the Honda 1¼ seconds.

Then t = 16.85 s

and x = 1.5m/s² * (16.85s)² = 426 m

and the Honda squeaks out a victory.

You could also just find the time it takes each to go 400 m:

Honda: t = √(2s/a) = √(800m / 3.0m/s²) = 16.3 s

Porsche: T = √(800m / 3.5m/s²) = 15.1 s

Since the Porsche only gives up 1 s at the beginning, it wins by 0.2 s.

Explanation:

6 0

3 years ago