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Elodia [21]
3 years ago
5

Question #3

Engineering
2 answers:
Mazyrski [523]3 years ago
7 0
It’s false. The small changes create a small impact
son4ous [18]3 years ago
5 0

Answer:

i think it's falsel *not sure*

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Roman55 [17]

Answer:

A range from 5,000 miles to 7,500 miles, on average. Some recommended intervals may be shorter or longer.

4 0
3 years ago
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With the help of diagrams explain the differences in the functions of electrostatic
ololo11 [35]

Answer:

Good Luck!

Explanation:

5 0
3 years ago
Q1: The first option should always be to get out safely (RUN)
nekit [7.7K]

Answer:

Q1 true

Q2 true

And other I am confuse

6 0
3 years ago
What is 220 C in degrees Fahrenheit (F)?
8_murik_8 [283]

Answer:

428°F

Explanation:

The equation to convert degrees Celsius to degrees fahrenheit is

°F (degrees fahrenheit) = (9/5 * °C (degrees celsius) ) + 32

°F = (9/5 * 220 °C (degrees celsius)) +32 = 428 °F (degrees fahrenheit)

4 0
3 years ago
An AC power generator produces 50 A (rms) at 3600 V. The voltage is stepped up to 100 000 V by an ideal transformer and the ener
RSB [31]

Given:

I_{rms} = 50 A

voltage, V = 3600V

step-up voltage, V' = 100000 V

Resistance of line, R = 100\ohm

Solution:

To calculate % heat loss in long distance power line:

Power produced by AC generator, P = 50\times 3600 W

P = 180000 W = 180 kW

At step-up voltage, V = 100000V or 100 kV

current, I = \frac{P}{V'}

I = \frac{1800000}{100000}

I = 1.8 A

Power line voltage drop is given by:

V_{drop} = I\times R

V_{drop} = 1.8\times 100

V_{drop} = 180 V

Power dissipated in long transmission line P_{dissipated} = V_{drop}\times I

Power dissipated in long transmission line P_{dissipated} = 180\times 1.8 = 324 W

% Heat loss in power line, P_{loss} = \frac{P_{dissipated}}{P}\times 100

% Heat loss in power line, P_{loss} = \frac{324}{180000}\times 100

P_{loss} = 0.18%

 

5 0
3 years ago
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