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RideAnS [48]
3 years ago
6

Q1: The first option should always be to get out safely (RUN)

Engineering
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

Q1 true

Q2 true

And other I am confuse

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What is the velocity of flow in an asphalt channel that has a hydraulic radius of 3.404 m, length of 200 m and bed slope of 0.00
yKpoI14uk [10]

Answer:

The velocity of flow is 10.0 m/s.

Explanation:

We shall use Manning's equation to calculate the velocity of flow

Velocity of flow by manning's equation is given by

V=\frac{1}{n}R^{2/3}S^{1/2}

where

n = manning's roughness coefficient

R = hydraulic radius

S = bed slope of the channel

We know that for an asphalt channel value of manning's roughness coefficient = 0.016

Applying values in the above equation we obtain velocity of flow as

V=\frac{1}{0.016}\times 3.404^{2/3}\times 0.005^{1/2}\\\\\therefore V=10.000m/s

7 0
3 years ago
How does the clearance volume affect the efficiency of the Otto cycle?
eduard

Answer:

Explanation:

A smaller clearance volume means a higher compression. A higher compression means better thermal efficiency. However a compression ratio too high might be troublesome, as it can cause accidental ignition of the fuel-air mix. This is the reason why Otto cycle engines have lower compressions that Diesel engines. In a Diesel engine the mix ignites by compression instead of a spark.

7 0
3 years ago
Write a function "funthree" that will print a box of characters. The function will always receive as the first input argument th
stiv31 [10]

Answer: i8g7ieusgr7eytuu7esieso87 sugr7pi8y8hiuh9yehroe998 rydyh9 t9ry9 7 fdgerje 78re87es 7yehr87ehtu9hu7b puuhihugogi;ghi uhugyug fhglhfu fufbiup hughghuihu fhuihihiuhg uhfuhuig8fguh hguihfhjliigihfuhf;gjihgh hfuyt8uyiiohiodohi

Explanation: so first you are going to hyigfgegidii9thdf5dh8yy7 gdiuigp 87hgiuf 8yhijh gihoighhgd

4 0
4 years ago
This is just so I can flip the picture
Pepsi [2]

Answer:

ok

Explanation:

thx for points

7 0
4 years ago
Calculate the density of a hydraulic oil in units of kg/m^3 knowing that the density is 1.74 slugs/ft^3. Then, calculate the spe
Amanda [17]

Answer:

Density of oil will be 897.292 kgm^3

And specific gravity of oil will be 0.897

Explanation:

We have given density of oil is 1.74 slugs/ft^3

We have to convert this slugs/ft^3 into kg/m^3

We know that 1 slugs = 14.5939 kg

So 1.74 slug = 1.74×14.5939 = 25.3933 kg

And 1 cubic feet = 0.0283 cubic meter

So 1.74slug/ft^3=\frac{1.74\times 14.5939kg}{0.0283m^3}=897.292kg/m^3

Now we have to calculate specific gravity it is the ratio of density of oil and density of water

We know that density of water = 1000 kg/m^3

So specific gravity of water =\frac{897.292}{1000}=0.897

7 0
4 years ago
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