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blagie [28]
3 years ago
11

How many moles are 2.60 * 10 ^ 27 atoms of Silicon?

Chemistry
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

~4,317.5 moles of Silicon

Explanation:

Using Avogadro's contant we know that:

1mole = 6.022 x 10^23 atoms

So,to calculate the number of moles in 2.60 x 10^27 atoms of Silicon:

=(2.60 x 10^27 x 1)/(6.022 x 10^23)

~4,317.5 moles of Silicon

Hope it helps:)

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4NH3+5O2=4NO+6H20 if 32.5 grams of NH3 react with enough oxygen, how many grams of water should form?
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51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

<h3>How to find the Number of moles ?</h3>

To calculate the number of moles use the formula

Number of moles = \frac{\text{Given Mass}}{\text{Molar Mass}}

                              = \frac{32.5}{17}

                              = 1.9 mol

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4 mol of NH₃ react with oxygen to given 6 mole of water.

So 1.9 mol of NH₃ produces = \frac{1.9}{4}\times 6

                                              = 2.85 mol of water

Mass of water = Molar Mass of water × Number of moles of water

                        = 18 × 2.85

                        = 51.3 gram

Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

Learn more about the Moles here: brainly.com/question/15356425

#SPJ1

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