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trapecia [35]
3 years ago
12

What is the product of 392 and 0.13592 with the correct sisignificant digits and proper scientific notation

Chemistry
2 answers:
WITCHER [35]3 years ago
4 0

the correct answer is-

 5.33*10

Mrrafil [7]3 years ago
4 0

Answer:

53.3

Explanation:

The product will be calculated as:

392 × 0.13592 = 53.28064

The correct number of significant figures corresponds to the <u>least number of significant figures in the initial values.</u>

  • 392 has 3 significant figures
  • 0.13592 has 5 significant figures

The least number is 3 significant figures, hence the result should also have 3 significant figures.

53.28064 should then be rounded to 53.3

This number could also be written as 5.33x10

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dezoksy [38]

The vital capacity will be 4600ml.

<h3>What is vital capacity?</h3>

The highest amount of air a person can inhale following their maximal exhalation is known as their vital capacity. It is equivalent to the total of the inspiratory, tidal, and expiratory reserve volumes. It roughly corresponds to Forced Vital Capacity. A wet or conventional spirometer can assess a person's vital capacity.

Normal people have a 3 to 5-liter vital capacity.

It enables simultaneous inhalation of the greatest possible volume of clean air and exhalation of the greatest possible volume of stale air. So, by increasing gaseous exchange between the body's various tissues, it improves the amount of energy available for bodily function.

VC = TV₊IRV₊ERV

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VC = Vital capacity

TV = Tidal volume

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ERV = expiratory reserve volume

VC = 500 ₊ 3000 ₊ 1100

VC = 4600ml

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To know more about  vital capacity refer to: brainly.com/question/14877276

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The decomposition reaction of carbon disulfide to carbon monosulfide and sulfur is first order with k = 2.80 ✕ ✕ 10−7 sec-1 at 1
madam [21]

Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.

              b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.

Explanation: The decomposition of carbon disulfide is given as:

                          CS_2(g)\rightarrow CS(g)+S(g)

at t=0                    4.83g             0          0

at t=37 days        4.83 - x            x           x

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x = amount of CS_2 utilised in the reaction

This reaction follows first order kinetics so the rate law equation is:

k=\frac{2.303}{t}log\frac{A_o}{A}

where, k = rate constant

t = time

A_o = Initial mass of reactant

A = Final mass of reactant

a) For this, the value of

k=2.80\times10^{-7}sec^{-1}

t = 370 days = 3196800 sec

A_o = 4.83

A = 4.83-x

Putting values in the above equation, we get

2.8\times 10^{-7}sec^{-1}=\frac{2.303}{3196800sec}log\left(\frac{4.83}{4.83-x}\right)

x = 2.85g

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b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.

Amount of carbon monosulfide formed = 2.85g

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A substance which melts/boils at a fixed temperature is a pure substance.<br><br> True<br> False
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