Answer:
3.59x10^21 molecules
Explanation:
1mole of a substance contains 6.02x10^23 molecules.
Therefore, 1mole of C8H18 will also contain 6.02x10^23 molecules
1mole of C8H18 = (12x8) +(18x1) = 96 + 18 = 114g.
1mole (i.e 114g) oh C8H18 contains 6.02x10^23 molecules.
Therefore, 0.68g of C8H18 will contain = (0.68 x 6.02x10^23)/114 = 3.59x10^21 molecules
The ballon would have deflated in order to decrease the volume
Hydrogen gas
Acid + metal = salt and hydrogen gas
Answer:
1,42 Å
Explanation:
La longitud de enlace de Bi-I se obtiene por
Bi-I = Radio del átomo de Bi + Radio del átomo de yodo
pero radio del átomo de yodo = 1.39Å
Longitud del enlace Bi-I = 2,81 Å
Por lo tanto, el radio del átomo de Bi = 2,81 Å - 1,39 Å
radio del átomo de Bi = 1,42 Å