All categories

3 years ago

Give an example of biotic living conditions.

Chemistry

2 answers:

Dafna11 [192]3 years ago

8 0

Answer:

water, light, wind, soil, humidity, minerals, gases

Explanation:

i just know

Brrunno [24]3 years ago

3 0

Answer:

plants and animals

Explanation:

You might be interested in

Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of h2c2o4 and h2o in th

postnew [5]

The balanced redox reaction, if it occurs in acidic solution, is

5C₂O₄²⁻(aq) + 2MnO₄⁻(aq) + 16H⁺-----> 10CO₂(g) + 2Mn²⁺(aq) + 8H₂O(l)

<h3>What are redox reaction?</h3>

Redox reactions are those in which loss and again of electrons occur.

To balance the redox reaction, we must first break the whole reaction into half equations;

Oxidation half equation

$\rm 5C_2O4^2^-(aq) + 10e + 8H^+----- > 10CO_2(g) + 4H_2O(l)$

Reduction half equation

$\rm 2MnO_4^- (aq) + 10e + 8H^+----- > 2Mn^2+(aq) + 4H_2O(l)$

Now combine both the reactions

$\rm 5C_2O_4^2-(aq) + 2MnO4^- (aq) + 16H^+----- > 10CO_2(g) + 2Mn^2+(aq) + 8H_2O(l)$

Thus, the coefficient of H₂C₂O₄ is 5 and that of water is 8.

Learn more about redox reactions

brainly.com/question/13293425

#SPJ4

8 0

2 years ago

How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?

natima [27]

Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

N₂: 1 mole
H₂: 3 moles
NH₃: 2 moles

The molar mass of the compounds is:

N₂: 14 g/mole
H₂: 2 g/mole
NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

N₂: 1 mole ×14 g/mole= 14 grams
H₂: 3 moles ×2 g/mole= 6 grams
NH₃: 2 moles ×17 g/mole=34 grams

<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

$moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}$

<u><em>moles of NH₃= 5.33 moles</em></u>

Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

4 0

2 years ago

How many molecules of N204 are in 85.0 g of N2O4?

alukav5142 [94]

Answer:

5.56 × 10^23 molecules

Explanation:

The number of molecules in a molecule can be calculated by multiplying the number of moles in that molecule by Avagadro's number (6.02 × 10^23)

Using mole = mass/molar mass

Molar mass of N2O4 = 14(2) + 16(4)

= 28 + 64

= 92g/mol

mole = 85.0/92

= 0.9239

= 0.924mol

number of molecules of N2O4 (nA) = 0.924 × 6.02 × 10^23

= 5.56 × 10^23 molecules

4 0

3 years ago

Determine the approximate amount of potassium hydrogen phthalate, KHP, that you will need to neutralize 6.00 ml of 0.100 M NaOH.

Sveta_85 [38]

Answer:

potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol

to get 1000 ml

Molar concentration = Mass concentration/Molar Mass

mass concentration = molar concentration x molar mass

mass concentration=0.1 M,

molar mass= 204.233 g/mol

so to get 1L

mass conc = 204.233 x 0.1

= 20.4233g for 1L or 1000 ml

to get 6.00 ml

if 20.4233g is for 1000ml

then to 6.00 ml

= 20.4233 x 6 / 1000

= 0.123g for 6.00 ml

according to the equation below

NaOH(aq) + KHC8H4O4(aq) --> KNaC8H4O4(aq) + H2O(l)

number of moles of NaOH is equal to that of KHP

so the same amount will be needed too, which is

= 0.123g

6 0

3 years ago

Where is energy stored in living sytems

EastWind [94]

Answer:

energy is stored in the chemical bonds in molecules

Explanation:

6 0

3 years ago