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3 years ago

In which way does a change in natural selection influence the evolution of affected species?

Chemistry

1 answer:

joja [24]3 years ago

8 0

Answer:c

Explanation:

Natural Selection is survival of the fittest

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What is the mass, in grams, of 7.27 x 10^8 Ne atoms?<br> I need answers it is almost due!!

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441

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4 years ago

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After completing an experiment, all chemical wastes should be an disposed of according to your instructor’s directions. be left

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3 years ago

Based on the following chemical equation how many hydrogen atoms are present in the products side?

OleMash [197]

The number of Hydrogen atoms = 6 atoms

<h3>Further explanation</h3>

Given

Reaction

N₂ + 3H₂ ⇒ 2NH₃

Required

The number of Hydrogen atoms

Solution

The reaction coefficient of a chemical equation shows the mole ratio of the reacting compound.

On a compound the reaction coefficient indicates the number of molecules

Whereas the subscript after the atom shows the number of atoms in that compound

Product from the reaction : 2NH₃

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= 2 x 3

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3 years ago

Which direction does thermal energy flow in the following diagram? the picture is of someone holding an ice cream cone

Sliva [168]

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3 years ago

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How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0

3 years ago