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3 years ago

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Explain the law of conservation of energy. Give a specific example using kinetic and potential energy that shows how energy is c

onserved.

1 answer:

stira [4]3 years ago

8 0

Answer:

Law of conservation of energy states that energy can neither be created nor can be destroyed but can be changed from one form to another

example:I am quite confused Sorry....❤plz follow me

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The materials created from a chemical reaction are called

sweet [91]

The answer would be products

8 0

3 years ago

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On a planet where the temperature is so high, the ground state of an electron in the hydrogen atom is n = 4. What is the ratio o

kvv77 [185]

Answer:

1:16

Explanation:

The ground state of an electron on the planet is n = 4 compared the ground state of an electron at n =1. For a hydrogen atom, the electron energy level is given as:

$E(n)=\frac{13.6}{n^2}\\ \\Where\ n\ is\ the\ ionization \ energy$

$E(4)=\frac{13.6}{4^2}=\frac{13.6}{16}\\ \\E(1)=\frac{13.6}{1^2}=\frac{13.6}{1}\\ \\The\ ratio\ of\ their\ ionization\ energy=\frac{E(4)}{E(1)} =\frac{\frac{13.6}{16} }{\frac{13.6}{1} } =\frac{1}{16}=1:16$

Hence the ratio of their ionization energies is 1:16

6 0

3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST!!! Its due tonight at 12:00

Dmitry [639]

Answer:

c

Explanation:

we have only distance vs time graph so c is the right answer that cart is moving with constant speed of 0.5m/s

confirmed

first calculate distance which is from 2 to 5.5

5.5-2=3.5

apply the formula of velocity

v=s/t

v=3.5/7=0.5

8 0

3 years ago

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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H2S(g) 3O2(g)2H2O(l) 2SO2

Marizza181 [45]

Answer:

$\Delta _rH=-1124.14kJ/mol$

Explanation:

Hello!

In this case, since the standard enthalpy change for a chemical reaction is stood for the enthalpy of reaction, for the given reaction:

$2H_2S(g) +3O_2(g)\rightarrow 2H_2O(l) +2SO_2(g)$

We set up the enthalpy of reaction considering the enthalpy of formation of each species in the reaction at the specified phase and the stoichiometric coefficient:

$\Delta _rH=2\Delta _fH_{H_2O,liq}+2\Delta _fH_{SO_2,gas}-2\Delta _fH_{H_2S,gas}-3\Delta _fH_{O_2,gas}$

In such a way, by using the NIST database, we find that:

$\Delta _fH_{H_2O, liq}=-285.83kJ/mol\\\\\Delta _fH_{SO_2, gas}=-296.84kJ/mol\\\\\Delta _fH_{O_2,gas}=0kJ/mol\\\\\Delta _fH_{H_2S,gas}=-20.50kJ/mol$

Thus, we plug in the enthalpies of formation to obtain:

$\Delta _rH=2(-285.73kJ/mol)+2(-296.84kJ/mol)-2(-20.50kJ/mol)-3(0kJ/mol)\\\\\Delta _rH=-1124.14kJ/mol$

Best regards!

8 0

2 years ago

Rank the following carboxylic acids from strongest (1) to weakest (4)

Paha777 [63]

Answer:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

Explanation:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

More electronegative atom of halogen is , stronger acid will be.

6 0

3 years ago