Question

A 1100 kg car strikes a wall with a force of 4000 N in 0.35 seconds. What is the change in the

Answer 1

Answer:

(v-u) = 1.27 m/s

Explanation:

Given that,

Mass of a car, m = 1100 kg

Force with which the wall strikes, F = 4000 N

Time, t = 0.35 s

We need to find the change in velocity of the car.

The net force acting on the car is given by :

F = ma

a is acceleration

$F=\dfrac{m(v-u)}{t}\\\\(v-u)=\dfrac{Ft}{m}\\\\(v-u)=\dfrac{4000\times 0.35}{1100}\\\\(v-u)=1.27\ m/s$

(v-u) is the change in velocity. Hence, the change in the velocity of the car is 1.27 /s.