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weqwewe [10]
4 years ago
13

How do you find velocity when given 3 numbers

Physics
1 answer:
forsale [732]4 years ago
4 0
In general, that's not possible, unless the three numbers relate to
very specific quantities. 

For example, if the three numbers are the object's height, temperature,
and cost, then they are of no help at finding the object's velocity.
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The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou
zlopas [31]

Answer:

q = 3.6 10⁵  C

Explanation:

To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth

          r = 6 , 37 106 m

          E = k q / r²

          q = E r² / k

          q = \frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}

          q = 4.5 10⁵ C

Now let's calculate the charge on the planet with E = 222 N / c and radius

           r = 0.6 r_ Earth

           r = 0.6 6.37 10⁶ = 3.822 10⁶ m

           E = k q / r²

            q = E r² / k

            q = \frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}

            q = 3.6 10⁵  C

4 0
3 years ago
Cell with structures labeled A, B, and C
sveticcg [70]
The answer is A. :)
6 0
3 years ago
Read 2 more answers
A 2.0-N force acts horizontally on a 10-N block that is initially at rest on a horizontal surface. The coefficient of static fri
Nady [450]

Answer:

None of the statement is false - all of them are true

Explanation:

Let's analyze each statement:

- The net force on the block is zero newtons. --> TRUE. In fact, the block is moving across the surface at constant speed: constant speed means zero acceleration, and according to Newton's second law,

F = ma

this also means a net force of zero newtons.

- The frictional force on the block has magnitude 3.0 N. --> TRUE. The horizontal acceleration of the block is zero, so the resultant of the horizontal forces must be zero:

F-F_f = 0

where F = 3.0 N is the horizontal push and F_f is the frictional force. From the equation, we find

F_f = F = 3.0 N

- The coefficient of kinetic friction between the block and the surface is 0.30. --> TRUE. The frictional force is 3.0 N, and its expression is

F_f = \mu_k (mg)

where \mu_k is the coefficient of kinetic friction and (mg)=10 N is the weight of the block. Solving for \mu_k, we find

\mu_k = \frac{F_f}{mg}=\frac{3 N}{10 N}=0.30

- The direction of the total force that the surface exerts on the block is vertically upward. --> TRUE. Since gravity is acting downward, and the block is not accelerating on the vertical direction neither, there must be an equal and opposite force acting upward on the block: and this force is the force exerted by the surface on the block.

- The block is not accelerated. --> TRUE: the block is moving at constant speed, so its acceleration is zero.

7 0
4 years ago
2. A sports car claims to increase its speed from rest to 25 m/s in 3.6 seconds. How far will the car go in
Kaylis [27]

Explanation:

we first find acceleration by

V=u +at (v is the final velocity,u the initial velocity,a the acceleration and t the time taken)

v=25 m/s

u=0

t=3.6s

substituting we get

25=0 + a (3.6)

25=3.6a (diving both sides by 3.6 we get)

a=6.94 m/s^2

to find distance we use the equation v^2=u^2 + 2ad

25^2 =0^2 + 2 (6.94)do

625=13.88d (dividing both sides by 13.88 we get );

d=45m

3 0
4 years ago
A circular swimming pool has a diameter of 24 ft, the sides are 5 ft high, and the depth of the water is 4 ft. how much work is
sesenic [268]
The pumping work has the equation written below:
W = mΔh,
where m is the mass
Δh is the difference in height

We determine the mass from the density of water which is 62.5 lb/ft³.
Density = Mass/Volume
Mass = m = Density*Volume
m = (62.5 lb/ft³)(π/4)(24 ft)² = 9,000π
The lb is in lbm or pound-mass. To convert it to pound-force, lbf, we use the g/gc conversion factor which is equal to 1 lbf/lbm. Thus,

W = (9,000π lbm)(5 ft - 4 ft)(1 lbf/lbm) = 28,274 lbf·ft
3 0
3 years ago
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