<em>optical</em><em> </em><em>fibre</em>
There is always a net force acting on the object, so it will have constant acceleration
When a 10-kg block is simultaneously pushed toward the east with 20N and toward the west with 15N, the combination of these forces on the block is 5N toward the East
Let's understand this problem in detail
Let which is in east direction
and which is acting in the west direction
Now,
But and are in opposite direction.
So let's rotate the force vector by 180 degrees which becomes
Now both and are in same directionof the forces are in a single line
Adding both of them, we get
=
= 20N - 15N = 5N, as both of the forces are in east direction hence, the net force is also acting in the east driection
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force in component form is given as
F~ = Fx ˆı + Fy ˆj
given that : Fx = 4 N, Fy = −3 N
hence the force equation looks like
F~ = 4 ˆı + (- 3) ˆj
F~ = 4 ˆı - 3 ˆj
displacement is given as
~s = sx ˆı + sy ˆj
given that : sx = 1 m, and sy = 1 m
hence the displacement is given as
~s = 1 ˆı + 1 ˆj
work done is the dot product of force and displacement . hence work done is given as
W = F~.~s
W = (4 ˆı - 3 ˆj) . (1 ˆı + 1 ˆj )
W = (4 x 1) ( ˆı.ˆı) - (3 x 1) (ˆj.ˆj)
W = 4 - 3
W = 1 J
θ = angle between F~ and ~s = ?
hence the work done by the force comes out to be 1 J
|F~| = magnitude of force = sqrt(Fx² + Fy²) = sqrt((4)² + (-3)²) = 5 N
|~s| = magnitude of displacement = sqrt(sx² + sy²) = sqrt((1)² + (1)²) = sqrt(2)
we know that work done is given as
W = |F~| |~s| Cosθ
1 = (5) (sqrt(2) Cosθ
Cosθ = 0.142
θ = Cos⁻¹(0.142)
θ = 81.84 deg
For the sound wave passing through regions of the ocean with varying density, longer wavelengths correspond to greater density of the water.
<h3>What is effect of density of a medium on wavelength of a wave?</h3>
The density of a medium is directly proportional to the wavelength of a wave.
The higher the density of the medium, the longer the wavelength of a wave.
Therefore, for a sound wave passing through regions of the ocean with varying density, longer wavelengths correspond to greater density of the water.
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