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docker41 [41]
2 years ago
14

A charge of 24 C pass a certain point in a conductor in 10 s. What is the size of current in the conductor?

Physics
2 answers:
arsen [322]2 years ago
8 0

Answer:

2.4A

Explanation:

I = Q/t

I = 24/10

= 2.4A

allsm [11]2 years ago
6 0

Answer:

write the name of any five districts of nepal

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During a chemical reaction, Bromine (Br) would be expected to
Andrew [12]

Answer:

During a chemical reaction, Bromine (Br) would be expected to  <u><em>gain 1 valence electron to have a full octet.</em></u>

Explanation:

In the periodic table the elements are ordered so that those with similar chemical properties are located close to each other.

The elements are arranged in horizontal rows, called periods, which coincide with the last electronic layer of the element. That is, an element with five electronic shells will be in the fifth period.

The columns of the table are called groups. The elements that make up each group coincide in their electronic configuration of valence electrons, that is, they have the same number of electrons in their last.

The elements tend to resemble the closest noble gases in terms of their electronic configuration of the last layer, that is, having eight electrons in the last layer to be stable.

Bromine belongs to group 17 (VII A), which indicates that it has 7 electrons in its last shell. So bromine requires more energy to lose all 7 electrons and generate stability, than it does to gain 1 electron and fill in 8 electrons to be stable. So:

<u><em>During a chemical reaction, Bromine (Br) would be expected to  gain 1 valence electron to have a full octet.</em></u>

6 0
2 years ago
Please need help on this one
Vitek1552 [10]

Answer:

B. Earth's internal heat is thermal energy generated from molten rock under great pressure.

7 0
2 years ago
Read 2 more answers
A tube of mercury with resistivity 9.84 × 10 -7 Ω ∙ m has an electric field inside the column of mercury of magnitude 23 N/C tha
slava [35]

Answer:

The current through the tube is 73.39A.

Explanation:

The relationship between the resistivity \rho, the electric field E, and the current density J is given by

\rho = \dfrac{E}{J}

This equation can be solved for J to get:

J = \dfrac{E}{\rho}

Since the current is I = J\cdot A

I= J\cdot A  = \dfrac{E}{\rho} \cdot A

Now, for the tube of mercury \rho = 9.84*10^{-7}\: \Omega \cdot m, E = 23N/C, and the area is A = \pi r^2 = \pi (1.0*10^{-3}m)^2 = 3.14*10^{-6}m^2; therefore,

I= \dfrac{23N/C}{9.84*10^{-7}\Omega\cdot m } *3.14*10^{-6}m^2

\boxed{I = 73.39A.}

Hence, the current through the mercury tube is 73.39A.

5 0
3 years ago
PLEASE HELP!<br>I need help with this
melisa1 [442]

A)

At time = .003 hr

B)

90* (3*10^-3) = .27km

C)

.005 hr

D)

Car A = 150 * (.005) = .75km

Car B = (90 * (.005) = .45 km

E)

Car A = 150 * (0.008) = 1.2 km

Car B = 90 * (0.008) = 0.72 km

Car A is ahead



3 0
3 years ago
Earth has a mass of 5.97 x 1024kg, and a mean radius of 6.38 x 10m. What would be the orbita
trapecia [35]

Answer:

v = 1630 m/s

T = 5.78 x 10^5 s

Explanation:

The tangential speed of the satellite can be found by requiring that the gravitational force on the satellite is equal to the centripetal force:

G\frac{Mm}{(R+h)^2}=m\frac{v^2}{R+h}

where

G is the gravitational constant

M=5.97 x 1024kg is the Earth's mass

m is the satellite's mass

R=6.38 \cdot 10^6 m is the Earth's radius

h=1.44\cdot 10^8 m is the altitude of the satellite

v is the speed of the satellite

Solving for v,

v=\sqrt{\frac{GM}{R+h}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24}kg)}{6.38\cdot 10^6 m+1.44\cdot 10^8 m}}=1627 m/s \sim 1630 m/s

And the period of the orbit is equal to the ratio between the distance covered during one revolution (the circumference of the orbit) and the speed:

T=\frac{2 \pi (R+h)}{v}=\frac{2\pi (6.38\cdot 10^6 m+1.44\cdot 10^8 m)}{1630 m/s}=5.79\cdot 10^5 s

So the correct answer is

v = 1630 m/s

T = 5.78 x 10^5 s

6 0
3 years ago
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