Question

If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.

Answer 1

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Charge$q=2\times10^{-4}C$

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

$V=\dfrac{E}{Q}$

$V=\dfrac{6.5}{2\times10^{-4}}$

$V=32500\ volt$

Hence, The electric potential difference is 32500 volt.