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jarptica [38.1K]
3 years ago
5

If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.

Physics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Chargeq=2\times10^{-4}C

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

V=\dfrac{E}{Q}

V=\dfrac{6.5}{2\times10^{-4}}

V=32500\ volt

Hence, The electric potential difference is 32500 volt.

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