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2 years ago

What do the valence of electrons tell you?

Chemistry

1 answer:

9966 [12]2 years ago

4 0

Answer:

valence electrons are the electrons that are located in the outermost electron shell of an element. Knowing how to find the number of valence electrons in a particular atom is an important skill for chemists because this information determines the kinds of chemical bonds that it can form and, therefore, the element's reactivity

Explanation:

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Scientists have speculated that element 126 might have a moderate stability allowing it to be synthesized and characterized. Pre

Dennis_Churaev [7]

Answer:

[Og] 5g2 6f3 8s2 8p1

Explanation:

Unbihexium, or element 126 is a hypothetical chemical element, until the element is discovered, confirmed and a permanent number is decided. This element is expected to be a g-block superactinide and the eight element in the 8th period.

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3 years ago

The R-COOH compound behaves as an _____. acid base alcohol ester

nadezda [96]

The correct answer is base

8 0

3 years ago

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In cells,____ are proteins that are needed to lower the amount of energy required to start chemical reactions.

Arturiano [62]

Answer:

Enzymes

Explanation:

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3 years ago

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A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0

miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

$Q_{metal} - Q_{water} = 0$

$Q_{metal} = Q_{water}$

Where:

$Q_{water}$ - Heat received by water, measured in joules.

$Q_{metal}$ - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

$m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})$

The specific heat of the metal is cleared within equation above:

$c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}$

If we know that $m_{water} = 0.237\,kg$ , $m_{metal} = 0.244\,kg$ , $c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}$ , $T_{w,o} = 10\,^{\circ}C$ , $T_{m,o} = 100.10\,^{\circ}C$ and $T = 15.30\,^{\circ}C$ , the specific heat of molybdenum is:

$c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}$

$c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}$

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

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3 years ago

Rank the ions in order of increasing basicity: CH3NH-, CH3CH2-, CH30-

Alexxx [7]

In order to find out the ranking of ions basicity, check the pKa values of each ions. The principle that you need to remember is that the stronger the acid the weaker the corresponding conjugate base. The pKa dictates acid value of the compound. The answer would be CH3NH, CH3O-, and CH3CH2-.

3 0

3 years ago