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il63 [147K]
3 years ago
5

If the half-life of an element is 150 years, how much of a 400 gram sample would remain in 750 years?

Chemistry
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:

y

Explanation:

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50cm3 of 1 mol/dm3 HCl at 30°C was mixed with 50cm3 of 1mol/dm3 NaOH at 30°C in a styrofoam calorimeter. The temperature of the
trapecia [35]

Answer:

-21 kJ·mol⁻¹  

Explanation:

Data:

                    H₃O⁺ +  OH⁻ ⟶ 2H₂O

       V/mL:    50         50  

c/mol·dm⁻³:   1.0         1.0

     

ΔT = 4.5 °C  

       C = 4.184 J·°C⁻¹g⁻¹

C_cal = 50 J·°C⁻¹

Calculations:

(a) Moles of acid

\text{Moles of acid} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}\\\\\text{Moles of base} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}

So, we have 0.050 mol of reaction

(b) Volume of solution

V = 50 dm³ + 50 dm³ = 100 dm³

(c) Mass of solution

\text{Mass of solution} = \text{100 dm}^{3} \times \dfrac{\text{1.00 g}}{\text{1 dm}^{3}} = \text{100 g}

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

     nΔH   +         mCΔT       + C_calΔT = 0

0.050ΔH + 100×4.184×4.5 +   50×4.5  = 0

0.050ΔH +          1883        +      225    = 0

                                  0.050ΔH + 2108 = 0

                                              0.050ΔH = -2108

                                                        ΔH = -2108/0.0500

                                                              = -42 000 J/mol

                                                              = -42 kJ/mol

This is the heat of reaction for the formation of 2 mol of water

The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.

5 0
3 years ago
In order to promote the common ion effect, the concentration of the common ion must first:_____.
Svet_ta [14]

We need to increase the concentration of common ion first, in order to promote the common ion effect

<h3>What is the Common ion effect?</h3>

It is an effect that suppresses the dissociation of salt due to the addition of another salt having common ions.

For example, a saturated solution of silver chloride in equilibrium has Ag⁺ and Cl⁻ . Sodium Chloride is added to the solution and has a common ion Cl⁻. As a result, the equilibrium shifts to the left to form more silver chloride. Thus, solubility of AgCl decreases.

The Equilibrium law states that if a process is in equilibrium and is subjected to a change

  • in temperature,
  • pressure,
  • the concentration of reactant or product,

then the equilibrium shifts in a particular direction, according to the condition.

Thus, an increase in the concentration of common ion promotes the common ion effect.

Learn more about common ion effect:

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The vertical columns are groups

The horizontal rows are periods

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SOME ONE HELP I FORGOT PIC!!! 20 POINTS AND BRAINLIEST!!!
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spindle fibers

i think the next is two nuclei and still together but that stage is not anaphase. Anaphase is when the sister chromatids are pulled apart

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Explain how the understanding of penetrating power can be used to protect yourself from different types of ionizing radiation.
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Answer:

Radiation is energy. It can come from unstable atoms that undergo radioactive decay, or it can be produced by machines. Radiation travels from its source in the form of energy waves or energized particles. There are different forms of radiation and they have different properties and effects.

Explanation:

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