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Temka [501]
4 years ago
13

How long would it take a car, starting from rest and accelerating uniformly in a straight line at 5m/s^2, to cover a distance of

200m?
Physics
1 answer:
finlep [7]4 years ago
5 0

Answer:

The time taken by the car is 8.94 seconds.

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Determine the acceleration that results when a 12 N net force is applied to a 3 kg object.
Vadim26 [7]

Heya!!

For calculate aceleration, let's applicate second law of Newton:

\boxed{F=ma}

⇒ Being:

→ F = Force = 12 N

→ m = Mass = 3 kg

→ a = aceleration = ?

Lets replace according formula and leave the "a" alone:

12\ N = 3\ kg * \textbf{a}

\textbf{a} = 12\ N / 3\ kg

\textbf{a} = 4\ m/s^{2}

Result:

The aceleration of the object is of <u>4 m/s²</u>

3 0
3 years ago
Boy A and Boy B are pulling on a rope. If the rope is not moving toward either boy, identify two balanced forces involving the r
natima [27]

Answer:

Hey

The rope isn't moving because each boy is pulling with the same force on opposite ends. That being said the bot pulling force is balanced.

Inside the rope are molecules connecting the whole thing together. The force they exert on each other must be equal because they aren't moving but are still exerting forces

7 0
3 years ago
A container with volume 1.83 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas
alisha [4.7K]

Answer:

The  pressure is  P =   1652 \  Pa

Explanation:

From the question we are told that

    The  volume of the container is  V  =  1.83  \ L =  1.83 *10^{-3 } \  m^3

     The mass of  N_2 is  m_n  =  0.246 \ g =  0.246 *10^{-3} \ kg

     The root-mean-square velocity is  v =  192 \ m/s

The  root -mean square velocity is mathematically represented as

      v =  \sqrt{ \frac{3 RT}{M_n  } }

Now the ideal gas law is mathematically represented as

      PV  =  nRT

=>   RT  =  \frac{PV}{n }

Where n is the number of moles which is mathematically represented as

         n =  \frac{ m_n }{M }

Where  M  is the molar mass of  N_2

So  

        RT  =  \frac{PVM_n }{m _n  }

=>    v =  \sqrt{ \frac{3 \frac{P* V  *  M_n }{m_n } }{M_n  } }

=>    v =  \sqrt{  \frac{ 3 *  P* V  }{m_n } } }

=>   P =   \frac{v^2   *  m_n}{3 *    V  }

substituting values

    =>    P =   \frac{( 192)^2   *  0.246 *10^{-3}}{3 *    1.83 *10^{-3} }

=>         P =   1652 \  Pa

       

     

3 0
3 years ago
Which of the following are examples of projectile motion?
denis-greek [22]

Answer:

A or C    I would pick C

Explanation:

8 0
4 years ago
Read 2 more answers
Technician A says that galvanic activity is the result of a poor ground connection. Technician B says that electrolysis can occu
Drupady [299]

Answer:

Only B is correct.

Explanation:

Electrolysis and galvanic activity are two different ways of the passage of electricity. Electrolysis occurs at a spontaneous reaction, and galvanic activity needs an external force to happen.

For example, a cell works by a redox reaction, in which a material reduces (gain electrons), and the other oxides (loses electrons). As higher is the standard reduction potential of a material, as easy is to it to reduces. Thus, if a cell works with the reduction happens with the material with low standard reduction potential, then it works by galvanic activity.

When electronics are connected to the house system, it's necessary to do the ground connection, which will allow the electrons that are dissipated to go to the earth. So, it is done incorrectly, the electrons flow to the equipment, which they natural path. So, the electrolysis can occur with a poor ground connection.

7 0
4 years ago
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