The density of the object is approximately 1.91 kg per m³.
42 kg is a measure of mass, and 22 m³ is a measure of volume. Knowing this, you can use the relationship
to solve for the object's density.
42 kg
22 m³
1.91 kg per m³.
Answer:
Electric Field at a distance d from one end of the wire is
Electric Field when d is much grater than length of the wire =
Explanation:
Given:
- Total charge over the length of the wire = Q
- Length of the wire = L
- Distance from one end of wire at which electric field is needed to find=d
Let dE be the Electric Field due to the small elemental charge on the wire at a distance x from the one end of the wire and let be the charge density of the wire
Now integrating it over the entire length varying x from x=d to x=d+L we have and replacing we have
When d is much greater than the length of the wire then we have
1+\dfrac{L]{d}≈1
So the Magnitude of the Electric Field at point P =