How much energy was absorbed

In this problem, you will analyze a system composed of two blocks, 1 and 2, of respective masses m1 and m2. To simplify the anal

storchak [24]

Answer:

c. Both forces have equal magnitudes.

Explanation:

According to Newton´s 3rd Law, the force exerted by a body on another one , is equal and opposite to the one that the second object exerts on the first one.

This does not depend on the masses of the objects, so it doesn´t matter that m₁ be greater than m₂.

As examples of this, we can mention the gravity force, the electrostatic force, the normal force, etc.

So, in this case, taking into account only the magnitudes, we can say:

F₁₂ = F₂₁

7 0

3 years ago

An automobile with a mass of 1240.00 kg has 3.99 m between

Vitek1552 [10]

Answer:

$948.15248\ N$

$5134.04751\ N$

Explanation:

$F_f$ = Force on front wheels

$F_r$ = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

$F_r=1240\times 9.81-F_f$

As the forces are conserved we have

$(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N$

On rear wheels

$F_r=1240\times 9.81-10268.09503\\\Rightarrow F_r=1896.30497\ N$

The force on each rear whees is $\dfrac{1896.30497}{2}=948.15248\ N$

Force on each front wheel is $\dfrac{10268.09503}{2}=5134.04751\ N$

8 0

3 years ago

A ball is tossed with a velocity of 10 m/s directed vertically upward from a window located 20 m above the ground. Determine the

marusya05 [52]

Answer:

Explanation:

Given

Initial velocity of ball $u=10\ m/s$

height of window $h=20\ m$

Using Equation of motion

$y=ut+\frac{1}{2}at^2$

where u=initial velocity

t=time

a=acceleration

As ball is already is at a height of 20 m so

$Y=ut+\frac{1}{2}at^2+20$

$Y=10\times t+0.5\times (-9.8)t^2+20$

$Y=-4.9t^2+10t+20$

(b)highest point is obtained at v=0

$v^2-u^2=2as$

where

v=final velocity

u=initial velocity

a=acceleration

s=displacement

$(0)-10^2=2\times (-9.8)\times s$

$s=\frac{100}{19.6}$

$s=5.102\ m$

Highest Point will be $s+20=25.102\ m$

(c)Time taken when the ball hit the ground i.e. at Y=0

$-4.9t^2+10t+20=0$

$t=3.28\ s$

impact velocity $v=\sqrt{2\times 9.8\times 25.102}$

$v=22.181\ m/s$

7 0

3 years ago

BRAINLIEST ANSWER!!!!!!!!!!!!!!!!!!!

zhuklara [117]

Home is like a shelter where it keeps us safe.

4 0

3 years ago

Read 2 more answers

If the frequency of the disorder in the population is 0.000081, what is the percentage of heterozygous carriers?

patriot [66]

The frequency of the disorder in the population is 0.000081, So, the percentage of heterozygous carriers would be 0.018.

Unlike homozygous, being heterozygous means you have two different alleles. You inherited a different version from each parent. In a heterozygous genotype, the dominant allele overrules the recessive one. Therefore, the dominant trait will be expressed. The recessive trait won't show, but you're still a carrier.

The presence of two different alleles at a particular gene locus. A heterozygous genotype may include one normal allele and one mutated allele or two different mutated alleles.

The Hardy-Weinberg equation is given by :

⇒ p² + 2pq + q² = 1

Here, p and q represent the individual allele frequencies.

Therefore, p² = frequency of homozygous condition represented by p.

q² = frequency of homozygous alleles represented by q.

and 2pq = frequency of heterozygous condition.

So, the correct answer is '2pq'.

⇒ (aa) q² = 0.000081,

⇒ (a) q = 0.009,

⇒ (A) p = 0.991,

⇒ (Aa) 2pq,

⇒ 0.018.

To learn more about heterozygous carriers here

brainly.com/question/17458395

#SPJ4

8 0

2 years ago