Answer:
The velocity of the motorboat after 6s is 24 m/s.
Explanation:
Given;
acceleration of the motorboat, a = 4.0 m/s²
initial velocity of the motorboat, u = 0
time of motion of the motorboat = 6s
Apply the following kinematic equation to determine the velocity of the motorboat after 6 ;
v = u + at
v = 0 + (4 x 6)
v = 24 m/s
Therefore, the velocity of the motorboat after 6s is 24 m/s.
Answer:
Momentum of block B after collision =
Explanation:
Given
Before collision:
Momentum of block A = 
= 
Momentum of block B = 
= 
After collision:
Momentum of block A = 
= 
Applying law of conservation of momentum to find momentum of block B after collision 
.
Plugging in the given values and simplifying.
Adding 200 to both sides.
∴ 
Momentum of block B after collision =
For every action there is an equal and opposite reaction." So that applies to a roller coaster, between the ride vehicles and the track. When a ride goes up and down the hill, it creates different forces onto the track.
Answer:
0.72 atm
Explanation:
Given that the atmospheric pressure on a mountain is 550 mmHg.
Where 1 atm is equal to 760 mmHg.
To Convert millimetre mercury (mmHg) into atmospheric pressure units (atm) , divide the magnitude of pressure by 760. That is,
Pressure = 550/760
Pressure = 0.724 atm
Therefore, pressure in atm is 0.72 atm in two significant figures
Answer:20/47 meter per second
Explanation:
Mass of arrow(ma)=0.25kg
Velocity of arrow(va)=12m/s
Mass of target(mt)=6.8kg
Velocity of target(vt)=0 since target is at rest
Conservation of linear momentum says that :
maxva+mtxvt=(ma+mt)V
V=(maxva+mtxvt)/(ma+mt)
V=(0.25x12+6.8x0)/(0.25+6.8)
V=3/(7.05)
V=20/47 meter per second
