Answer:
Explanation:
We shall apply Gauss's theorem for electric flux to solve the problem . According to this theorem , total electric flux coming out of a charge q can be given by the following relation .
∫ E ds = q / ε
Here q is assumed to be enclosed in a closed surface , E is electric intensity on the surface so
∫ E ds represents total electric flux passing through the closed surface due to charge q enclosed in the surface .
This also represents total flux coming out of the charge q on all sides .
This is equal to q / ε where ε is a constant called permittivity which depends upon the medium enclosing the charge . For air , its value is 8.85 x 10⁻¹² .
If charge remains the same but radius of the sphere enclosing the charge is doubled , the flux coming out of charge will remain the same .
It is so because flux coming out of charge q is q / ε . It does not depend upon surface area enclosing the charge . It depends upon two factors
1 ) charge q and
2 ) the permittivity of medium ε around .
The answer is C, because it hits a dense medium, which causes it to bounce off.
Hope I helped. :)
The electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
<h3>What is electric potential energy?</h3>
Electric potential energy can be defined as the energy needed to move a charge against an electric field.
It is calculated using the formula;
U = Kq1 q2 ÷ r
Where Q = electric potential energy
k = Coulombs constant
q1 and q2 = charges
r = distance of separation
Electric potential energy is inversely proportional to the distance of separation of the charges.
If the distance of the charges changes from 3mm to 6mm, then the electric potential energy of the charges is reduced because it decreases with increase in the distance of the charges.
Therefore, the electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
Learn more about electric potential energy here:
brainly.com/question/14812976
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Explanation:
In geology, there are 5 divisions of time on the time scale. They are:
- eons
- eras
- periods
- epochs
- ages
Eons are the largest time period, while ages are the shortest time period. The rest of the above listed are in between the two.
Answer:
θ₁ = 5.4°
θ₂ = 10.86°
Explanation:
The angle ca be found by using grating equation:
mλ = d Sinθ
where,
m = order of diffraction
λ = wavelength = 405.3 nm = 4.053 x 10⁻⁷ m
d = grating element = 1/230 lines/mm = 0.0043 mm/line = 4.3 x 10⁻⁶ m/line
θ = angle = ?
FOR m = 1:
(1)(4.053 x 10⁻⁷ m) = (4.3 x 10⁻⁶ m/line) Sin θ₁
Sin θ₁ = 0.09425
θ₁ = Sin⁻¹(0.09425)
<u>θ₁ = 5.4°</u>
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FOR m = 2:
(2)(4.053 x 10⁻⁷ m) = (4.3 x 10⁻⁶ m/line) Sin θ₁
Sin θ₂ = 0.1885
θ₂ = Sin⁻¹(0.1885)
<u>θ₂ = 10.86°</u>
