All categories

2 years ago

I need help what is 145 marked up 175%

1 answer:

7 0

First you multiply 145 by 01.75 to get how much you add to the total. You add 253.75 to 145 and get 398.75 as the answer

You might be interested in

Can someone answer this for me?

Sophie [7]

Answer:

D 26

Step-by-step explanation:

154+154=308

308-360=52

52 divided by 2

=26

7 0

3 years ago

Read 2 more answers

Lynda has 27 fewer fish than Jack. Jack has 80.

Zielflug [23.3K]

Lynda had 53 fewer fish then jack did

8 0

2 years ago

Read 2 more answers

Please help

murzikaleks [220]

Answer:

$74.41

Step-by-step explanation:

x = Amount of money Sylvia had in her account

Amount of money spent at the Grocery Store= $25.89

Remaining Amount of money after Grocery = $48.52

Hence, By adding the two amount above we get the amount Sylvia had in her account before grocery;

x = $25.89 + $48.52

x = $74.41

6 0

2 years ago

2x+3y=4

garri49 [273]

Answer:

Option D.

Step-by-step explanation:

we have

$2x+3y=4$ -----> equation A

$2x-5y=-12$ -----> equation B

Solve the system by elimination

Multiply both sides equation A by -1

$-1(2x+3y)=-1(4)$

$-2x-3y=-4$ -----> equation C

Adds equation C and equation B

$-2x-3y=-4\\2x-5y=-12\\------\\-3y-5y=-4-12\\-8y=-16\\y=2$

<em>Find the value of x</em>

substitute the value of y in either equation

$2x+3(2)=4\\2x+6=4\\2x=-2\\x=-1$

The solution is the point (-1,2)

In this problem Option A,B and C are correct

The option D not result in a system with a pair of opposite terms

because

Multiply both sides of equation B by -3

$-3(2x-5y)=-3(-12)$

$-6x+15y=36$ -----> equation C

Multiply both sides of equation A by 5 $5(2x+3y)=5(4)$

$10x+15y=20$ ----> equation D

equation C and equation D not have a pair of opposite terms

5 0

2 years ago

(3a2 + 2ab + 2b) + (5a2 − 3ab + 9)

ivann1987 [24]

Step-by-step explanation:

$\tt{(3 {a}^{2} + 2ab + 2b) + (5 {a}^{2} - 3ab + 9})$

~While adding , the sign of each term of second expression remains same. So, Remove the unnecessary parentheses :

⤑ $\tt{3 {a}^{2} + 2ab + 2b + 5 {a}^{2} - 3ab + 9}$

~Like terms are those which have the same base. Combine the like terms :

⤑ $\tt{3 {a}^{2} + 5 {a}^{2} + 2ab - 3ab + 2b + 9}$

⤑ $\sf{8 {a}^{2} - ab + 2b + 9}$

$\red{ \boxed{ \boxed{ \tt{ ⟿ Our \: final \: answer : 8 {a}^{2} - ab + 2b + 9}}}}$

Hope I helped ! ツ

Have a wonderful day / night ♡

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

6 0

3 years ago

Read 2 more answers