Answer: 3002.86kg
Explanation:
Hydraulic cylinder diameter =125mm
Ambient pressure =1bar
Pressure =2500kpa
Piston Mass (MP) =?
F|(when it moves upward )=PA=F|(when it moves downward) =PoA+Mpg
Po=1 bar=100kpa
A=(π/4)D^2=(π/4)*0.125^2=0.01227m^2
Mp=(P-Po) A/g=(2500-100)*1000*0.01227/9.80665
Mp=3002.86kg.
Answer:
(a)Volume in liters=5.3 liters.
(b)Volume in liters/minute=31.8 liters/minute.
Explanation:
Given:
Diameter of cylinder ,D=150 mm
Stroke,L=300 mm
Time ,t=10 sec
we know that swept volume of cylinder
So
(a) Volume in liters =5.3 liters ( 1=1000 liters)
(b) When we divide swept volume by time(in minute) we will get liters/minute.
We know that 1 minute=60 sec
⇒10 sec= minute
So volume displace in liters/minute=31.8 liters/minute.
Answer:
MUDA MUDA A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Explanation:
Answer:
The pressure that the water exerts on the bottom of the tank is 59.2 kPa
Explanation:
Given;
height of tank, h = 5m
height of water in the tank, = 4m
pressure at the top of the tank, = 20 kPa
The pressure exerted by water at the bottom of the tank is the sum of pressure on water surface and pressure due to water column.
Therefore, the pressure that the water exerts on the bottom of the tank is 59.2 kPa