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KonstantinChe [14]
2 years ago
14

What is the molarity of a solution that contains 2.14 moles (CH3)2SO in 2.00 L solution?

Chemistry
1 answer:
seraphim [82]2 years ago
3 0
<h3>Answer:</h3>

1.07 M

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Molarity = moles of solute / liters of solution
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 2.14 moles (CH₃)₂SO

[Given] 2.00 L

[Solve] Molarity

<u>Step 2: Solve</u>

  1. Substitute in variables [Molarity]:                                                                    x M = 2.14 moles (CH₃)₂SO / 2.00 L solution
  2. [Molarity] Divide:                                                                                               x = 1.07 M
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A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10
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Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

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Step 3: Calculate the number of moles hydrocyanic acid (HCN)

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Step 4: Calculate the limiting reactant

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pOH = -log (0.0149)

pOH = 1.83

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