Answer: They create antibodies.
The distance covered is 1000 m
Explanation:
The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

where
s is the distance covered
v is the final velocity
t is the time
a is the acceleration
For the rocket in this problem, we have:
v = 445 m/s is the final velocity
is the acceleration
t = 4.50 s is the time
Substituting, we find the distance covered:

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Answer:
Distance, d = 61.13 ft
Explanation:
It is given that,
Initial speed of the car, u = 50 mi/h = 73.34 ft/s
Finally, it stops i.e. v = 0
Deceleration of the car, 
We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :



s = 61.13 ft
So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.
The mass of the man would remain the same…
His weight would change. Assuming the man’s weight on earth is 60N.
Since weight is a force, according to Newton’s second law, F = ma ( m = mass, a = acceleration due to gravity) First lets find the mass of the man, as it is required to find his weight on the moon.
F=ma[taking a of earth as10m/s
2
]
60=m.10[divide10onbothsides]
m=
10
60
= 6 Kg
Acceleration due to gravity on the moon is83%less than the acceleration due to gravity on earth(1.622m/s
2
).
F=ma
F=6.1.622=9.732 N
So a person weighting 60N on earth would approximately weight around 10Non the moon.
Answer:
The answer to your question is 75 cm²
Explanation:
To solve this problem, we need to use the Pascal's principle that states that the pressure in a point is equal to the pressure in a second point.

Process
1.- Solve for A2

2.- Substitution

3.- Simplification and result

A2 = 75 cm²