Answer:
20.96 m/s^2 (or 21)
Explanation:
Using the formula (final velocity - initial velocity)/time = acceleration, we can plug in values and manipulate the problem to give us the answer.
At first, we know a car is going 8 m/s, that is its initial velocity.
Then, we know the acceleration, which is 1.8 m/s/s
We also know the time, 7.2 second.
Plugging all of these values in shows us that we need to solve for final velocity. We can do so by manipulating the formula.
(final velocity - initial velocity) = time * acceleration
final velocity = time*acceleration + initial velocity
After plugging the found values in, we get 20.96 m/s/s, or 21 m/s
Answer:
4 m/s² down
Explanation:
We'll begin by calculating the net force acting on the object.
The net force acting on the object from the left and right side is zero because the same force is applied on both sides.
Next, we shall determine the net force acting on the object from the up and down side. This can be obtained as follow:
Force up (Fᵤ) = 15 N
Force down (Fₔ) = 25 N
Net force (Fₙ) =?
Fₙ = Fₔ – Fᵤ
Fₙ = 25 – 15
Fₙ = 10 N down
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass (ml= 2.5 Kg
Net force (Fₙ) = 10 N down
Acceleration (a) =?
Fₙ = ma
10 = 2.5 × a
Divide both side by 2.5
a = 10 / 2.5
a = 4 m/s² down
Therefore, the acceleration of the object is 4 m/s² down
Answer:
Explanation:
From the given information:
The initial PE
= m×g×h
= 5 kg × 9.81 m/s² × 10 m
= 490.5 J
The change in Potential energy P.E of the box is:
ΔP.E = ![P.E_f -P.E_i](https://tex.z-dn.net/?f=P.E_f%20-P.E_i)
ΔP.E = 0 -
ΔP.E = ![-P.E_i](https://tex.z-dn.net/?f=-P.E_i)
If we take a look at conservation of total energy for determining the change in the internal energy of the box;
![\Delta P.E + \Delta K.E + \Delta U = 0](https://tex.z-dn.net/?f=%5CDelta%20P.E%20%2B%20%5CDelta%20K.E%20%2B%20%5CDelta%20U%20%3D%200)
![\Delta U = -\Delta P.E - \Delta K.E](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20-%5CDelta%20P.E%20-%20%5CDelta%20K.E)
this can be re-written as:
![\Delta U =- (-\Delta P.E_i) - \Delta K.E](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D-%20%28-%5CDelta%20P.E_i%29%20-%20%5CDelta%20K.E)
Here, K.E = 0
Also, 70% goes into raising the internal energy for the box;
Thus,
![\Delta U =(70\%) \Delta P.E_i-0](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%2870%5C%25%29%20%5CDelta%20P.E_i-0)
![\Delta U =(0.70) (490.5)](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%280.70%29%20%28490.5%29)
ΔU = 343.35 J
Thus, the magnitude of the increase is = 343.35 J
The image is always virtual and erect. The image is highly diminished or point sized. It is always formed between F and P.
Answer:
V = IR
Explanation:
Voltage is denoted by V, current is denoted by I and resistance is denoted by R. Voltage is the difference of electric potential between two points. Current is the measure of the rate of flow of electric charge. Resistance is a measure how a device reduces the current flow through itself.
The three properties are related to each other as per the Ohm's law which states that voltage and current are directly proportional to each other, it can be denoted as
Voltage (V) = Current(I) X Resistance(R).
![V = I \times R](https://tex.z-dn.net/?f=V%20%3D%20I%20%5Ctimes%20R)