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Inessa05 [86]
2 years ago
8

How many moles of H are present in 3 moles of carbon trihydride?

Chemistry
1 answer:
PSYCHO15rus [73]2 years ago
8 0

Answer:

answer is  b.12

Explanation:

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Name the separation technique illustrated in the picture.<br><br> Chemistry Homework 80 points!
solmaris [256]

A. Filtration

This is because of the layers of Filter it goes through to make sure it is pure.

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You just got home from a run on a hot Atlanta afternoon. You grab a 1.00 liter bottle of water and drink three quarters of it in
-Dominant- [34]

Answer:

¾ litters of water was consumed

2.24 litters = 1 mole of water

Therefore ¾÷2.24 moles was consumed

0.33 moles

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3 years ago
What is the acceleration of the object’s motion? 0.5 m/s2 -0.5 m/s2 2 m/s2 -2 m/s2
djverab [1.8K]

Answer:  -2m/s2

Explanation:

Using the following equation ; acceleration = Change in velocity / time

i.e  a =  v - u / t

where  'a'  = acceleration

              v  = final velocity

              u  =  initial velocity

              t   =  time

Therefore;  from the graph we have acceleration to be, 0 - 6m/s / 3s  = -2m/s2

5 0
3 years ago
How many liters of a 0.30M solution are needed to give 2.7 moles of solute? Your answer:
OverLord2011 [107]
You HAVE TO know that molarity (M) tells you the number of moles of a solute per Liters of solution.
M=mol/L
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Volume = 2.7 mol/3.0 L
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3 years ago
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When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo
Marta_Voda [28]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

b)

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

7 0
2 years ago
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