Answer:
A. Calculate vector
B. Update vector of each object
C. Update position of each object
Explanation:
Taking assumption of a system in which the forces are a function of the previous step's final position:
Firstly, we calculate the (vector) forces acting on the objects.
Secondly, Update the (vector) momentum of each object
(note: also update the velocity).
Thirdly, Update the (vector) position of each object.
The other operations are as follows;
i. select (dt),
ii. define mass,
iii. Put down constants,
iv. initialize variables, this would occur before the time-step loop is entered.
Answer:
Time taken for the car to travel a distance of 4.50 m = 1.40 seconds
Explanation:
velocity of toy car = 3.21 m/s
distance travelled by toy car = 4.50 m
Time = ?
![Velocity = \frac{Distance}{Time} \\Time =\frac{Distance}{Velocity}](https://tex.z-dn.net/?f=Velocity%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D%20%5C%5CTime%20%3D%5Cfrac%7BDistance%7D%7BVelocity%7D)
![Time = \frac{4.50}{3.21} \\Time = 1.40s](https://tex.z-dn.net/?f=Time%20%3D%20%5Cfrac%7B4.50%7D%7B3.21%7D%20%5C%5CTime%20%3D%201.40s)
Therefore, the time taken for the car to travel a distance of 4.50 m = 1.40 seconds
The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still.
Answer:
is the drop in the water temperature.
Explanation:
Given:
- mass of ice,
![m_i=14.7\ g=0.0147\ kg](https://tex.z-dn.net/?f=m_i%3D14.7%5C%20g%3D0.0147%5C%20kg)
- mass of water,
![m_w=324\ g=0.324\ kg](https://tex.z-dn.net/?f=m_w%3D324%5C%20g%3D0.324%5C%20kg)
Assuming the initial temperature of the ice to be 0° C.
<u>Apply the conservation of energy:</u>
- Heat absorbed by the ice for melting is equal to the heat lost from water to melt ice.
<u>Now from the heat equation:</u>
![Q_i=Q_w](https://tex.z-dn.net/?f=Q_i%3DQ_w)
......................(1)
where:
latent heat of fusion of ice ![=333.55\ J.g^{-1}](https://tex.z-dn.net/?f=%3D333.55%5C%20J.g%5E%7B-1%7D)
specific heat of water ![=4.186\ J.g^{-1}.^{\circ}C^{-1}](https://tex.z-dn.net/?f=%3D4.186%5C%20J.g%5E%7B-1%7D.%5E%7B%5Ccirc%7DC%5E%7B-1%7D)
change in temperature
Putting values in eq. (1):
![14.7 \times 333.55=324\times 4.186\times \Delta T](https://tex.z-dn.net/?f=14.7%20%5Ctimes%20333.55%3D324%5Ctimes%204.186%5Ctimes%20%5CDelta%20T)
is the drop in the water temperature.