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3 years ago

WHAT IS PIVOT POINT ?

2 answers:

7 0

In financial markets, a pivot point is a price level that is used by traders as a possible indicator of market movement. A pivot point is calculated as an average of significant prices from the performance of a market in the prior trading period.

geniusboy [140]3 years ago

3 0

Pivots Points are price levels chartists can use to determine intraday support and resistance levels

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A current of 310 amps is flowing through a copper wire with a resistance of 30 ohms. What is the voltage?

torisob [31]

Answer:

the voltage is 930V

Explanation:

U=I*R

U=310*30=930V

8 0

2 years ago

The primary colors of light are A. red, yellow, and blue. B. red, white and blue. C. blue, green, and red. D. cyan, magenta, and

zhuklara [117]

I think it is A I hope I helped you

3 0

2 years ago

Read 2 more answers

The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the

PIT_PIT [208]

The drag force is directly proportional to the square of the velocity of motion of the object. So as the speed is doubled, the magnitude of drag force will get quadrupled.

<u>Explanation: </u>

Drag force is the opposing or resisting force acting on any object by the medium in which it is moving. So in this case, you are riding a bicycle, thus the medium can be considered as air.

The formula for calculating drag force is as below:

$\text {Drag force }=\frac{1}{2} \rho v^{2} C_{D} A$

Here, ρ is the density of the air molecules, v is the velocity or speed of the bicycle, CD is the drag coefficient and A is the area of the bicycle.

In the above equation, only the term velocity will be a varying quantity with respect to time and other quantities will remain constant throughout the single situation of riding of bicycle.

So, the equation can be,

$\text { Drag force }=k v^{2}$

Where ,

$k=\frac{1}{2} \rho C_{D} A$ (constant for this whole condition)

Now given the speed of bicycle increased from v to 2v, so the initial drag force will be

$N_{i}=k v^{2}$

After increase in speed, the final drag force will be

$N_{f}=k(2 v)^{2}$

$N_{f}=4 k v^{2}=4 N_{i}$

Thus, if the speed of the bicycle is doubled, the drag force will get increased by four times.

4 0

3 years ago

PLEASE HELP :)

Tom [10]

1) in the opposite direction always
2) drag force is the force that acts in the opposite direction of the applied force (air resistance if a drag force for example)
3) frictions forces between the sole and the ground as the owner walks
4) chalk would glide very easily, so a creaking sound could never be produced, but also one could not write anything on the board!
5) I apologize for my lack of familiarity with the kind of sport but the probable answer is to raise the friction of their hands in order to decrease slipping and get a tighter, more firm grip

6 0

2 years ago

The power ratings of several motors are listed in the table. A 2 column table with 3 rows. The first column is labeled motor wit

Lapatulllka [165]

The statement " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

Advertisement Rules:

An advertiser can not compare its products using the other companies name.

An advertiser can not make the false statement in its advertisement.

Here, the brand-W has the power rating of 7,640 W that is less than brand-Y. Advertiser cannot compare his brand using the name of Brand X, Y, or Z.

Therefore, the statement " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

To know more about Advertisement Rules:

brainly.com/question/13679377

7 0

2 years ago