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ioda
3 years ago
9

Unlike mechanical waves, electromagnetic waves do not require to travel through.

Physics
2 answers:
Nuetrik [128]3 years ago
6 0
The electromagnetic waves do not need any medium to travel as they are not mechanical in nature. They propagate in the form of electric and magnetic energy having a perpendicular vector of its velocity wave
Aleksandr-060686 [28]3 years ago
5 0
Unlike mechanical waves, electromagnetic waves do not require to medium through, Electromagnetic waves are the medium thru and which all exists as in Dr Wolff's Wave of Structure of matter.
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You collect some more data on that horse at a later time interval, but now you are measuring thehorse’s velocity, not its positi
Monica [59]

Answer:

a)  x(t) = 10t + (2/3)*t^3

b) x*(0.1875) = 10.18 m

Explanation:

Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.

Given:

- v(t) = 10 + 2*t^2 (radar gun)

- x*(t) = 10 + 5t^2 + 3t^3  (our coordinate)

Find:

-The position x of horse as a function of time t in radar system.

-The position of the horse at x = 2m in our coordinate system

Solution:

- The position of horse according to radar gun:

                              v(t) = dx / dt = 10 + 2*t^2

- Separate variables:

                              dx = (10 + 2*t^2).dt

- Integrate over interval x = 0 @ t= 0

                             x(t) = 10t + (2/3)*t^3

- time @ x = 2 :

                              2 = 10t + (2/3)*t^3

                              0 = 10t + (2/3)*t^3 + 2

- solve for t:

                              t = 0.1875 s

- Evaluate x* at t = 0.1875 s

                              x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3

                              x*(0.1875) = 10.18 m

3 0
3 years ago
Suzie Spacewalker hovers in space beside a rotating space station in outer space. Both she and the center of mass of the space s
Inga [223]

Answer:

is in the earths orbit

Explanation:

for Suzie to hover in space beside the rotating space station, she and the center  of mass of the space station are at relative rest which happens when space station is in Earth orbit, hence she is  in the earths orbit.

3 0
3 years ago
A student notices that a reaction takes place faster when the temperature is higher. Which best explains why this happens?
Pavel [41]

The reason why the reaction takes place faster when the temperature is higher is that the collision of particles of the object increases. In order to have a faster reaction, you would need the particles of the object to get excited and increase its collision to other particles. This can be achieved through increasing the temperature. 

8 0
3 years ago
How many atoms of each element are in the chemical formula P205?
Irina-Kira [14]

2 atoms of P (phosphorus) and 5 atoms of O (oxygen)

Explanation:

The chemical formula of a generic compound is written as

A_n B_m

where

A and B are the symbols of the elements contained in the compound

n and m are the number of atoms of each element, A and B respectively

In this problem, the compound given is

P_2 O_5

where:

- P is the symbol of the chemical element phosphorus

- O is the symbol of the chemical element oxygen

We see that the number following P is 2, so there are 2 atoms of phosphorus, while the number following O is 5, so there are 5 atoms of oxygen.

Learn more about compounds here:

brainly.com/question/10216585

brainly.com/question/2861241

brainly.com/question/10585691

#LearnwithBrainly

5 0
3 years ago
La velocidad de un tren se reduce uniformemente de 12m/s a 5m/s. Sabiendo que durante ese tiempo recorre una distancia de 100 m.
KATRIN_1 [288]

Responder:

Explicación:

Dados los siguientes datos

Valor inicial u = 12 m / s

velocidad final v = 5 m / s

Distancia S = 100 m

Necesario

aceleración del tren.

Usando la ecuación de movimiento

v² = u² + 2as

2as = v²-u²

a = v²-u² / 2s

Sustituyendo los valores dados para obtener la aceleración que tenemos;

a = 5²-12² / 2 (100)

a = 25-144 / 200

a = -119/200

a = -0,595 m / s²

Por tanto, la aceleración del tren durante este período es de -0,595 m / s²

b) Si el tren viaja a una parada desde 5 m / s, su velocidad final será cero y su velocidad inicial u será 5 m / s

Para obtener la distancia durante este período, sustituiremos u = 5 m / s, v = 0 m / sy a = -1,19 m / s² en la ecuación de movimiento anterior;

v² = u² + 2as

0² = 5²-2 (0.595) s

0 = 25-1,19 s

1,19 s = 25

s = 25 / 1,19

Responder:

Explicación:

Dados los siguientes datos

Valor inicial u = 12 m / s

velocidad final v = 5 m / s

Distancia S = 100 m

Necesario

aceleración del tren.

Usando la ecuación de movimiento

v² = u² + 2as

2as = v²-u²

a = v²-u² / 2s

Sustituyendo los valores dados para obtener la aceleración que tenemos;

a = 5²-12² / 2 (100)

a = 25-144 / 200

a = -119/200

a = -0,595 m / s²

Por tanto, la aceleración del tren durante este período es de -0,595 m / s²

b) Si el tren viaja a una parada desde 5 m / s, su velocidad final será cero y su velocidad inicial u será 5 m / s

Para obtener la distancia durante este período, sustituiremos u = 5 m / s, v = 0 m / sy a = -1,19 m / s² en la ecuación de movimiento anterior;

v² = u² + 2as

0² = 5²-2 (0.595) s

0 = 25-1,19 s

1,19 s = 25

s = 25 / 1,19

s = 21,0 m

Por lo tanto, la distancia que recorre hasta detenerse asumiendo la misma aceleración es 21.0 m

3 0
3 years ago
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