Answer:
y= -x +2
Step-by-step explanation:
y-y1 = m(x-x1)
y - 0 = 1(x - (-2))
y = -x + 2)
y = x + 2.
The first option,
both have to be negative, because they were originally both part of the one fraction, which was all negative.
Answer:
D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.
Step-by-step explanation:
We will test the hypothesis on the difference between means.
We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).
Then, the difference between means is:

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.
This is approximately 2 standards deviation (z=2).
The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.
Answer:
492.99
Step-by-step explanation: x = amount invested at 12%
y = amount invested at 9%
---
x + y = 20287
0.12x = 0.09y + 492.99
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put the system of linear equations into standard form
---
x + y = 20287
0.12x - 0.09y = 492.99
To solve for P(QIR) we use the formula:
P(QIR)=[P(Q∩R)]/P(R)
But from the diagram:
P(Q∩R)=3/22
P(R)=7/22
hence
P(QIR)=3/22÷7/22=3/7