Answer:
Fuel efficiency for highway = 114.08 miles/gallon
Fuel efficiency for city = 98.79 miles/gallon
Explanation:
1 gallon = 3.7854 litres
1 mile = 1.6093 km
Let's first convert the efficiency to km/gallon:
48.5 km/litre = (48.5 * 3.7854) km/gallon
48.5 km/litre = 183.5919 km/gallon (highway)
42.0 km/litre = (42.0 * 3.7854) km/gallon
42.0 km/litre = 158.9868 km/gallon (city)
Next, we convert these to miles/gallon:
183.5919 km/gallon = (183.5919 / 1.6093) miles/gallon
183.5919 km/gallon = 114.08 miles/gallon (highway)
158.9868 km/gallon = (158.9868 /1.6093) miles/gallon
158.9868 km/gallon = 98.79 miles/gallon (city)
Answer: True
Explanation: Injector orifice is the factor which describes the size of the opening of the injector .There are different pattern and size of the opening for the injector which affects the mixture of the chemical substance that is used for the production of the energy that is known as propellant.
The pattern and size of the orifice will define the variation in the amount of energy that could be produced.Thus the statement given is true.
Answer:
μ = 0.136
Explanation:
given,
velocity of the car = 20 m/s
radius of the track = 300 m
mass of the car = 2000 kg
centrifugal force


F c = 2666. 67 N
F f= μ N
F f = μ m g
2666.67 = μ × 2000 × 9.8
μ = 0.136
so, the minimum coefficient of friction between road surface and car tyre is equal to μ = 0.136
Answer:
Ethics
Explanation:
To do the right thing or to have moral principles is called ethics. Ethics affect how people make decisions and lead their lives. Some words people associate with ethics includes:
- Honesty
- Integrity
- Promise keeping and Trustworthiness
- Loyalty
- Fairness
- Concern for others
- Respect for others
- Law abiding
etc.
Answer:

Explanation:
Given data:
Ammonia Nitrogen 30 mg/L
pH = 8.5
-log[H +] = 8.5
[H +] = 10^{-8.5}

Rate constant is given as
...........1

Total ammonia as NItrogen is given as 30 mg/l
![\%NH_4^{+} = \frac{ [NH_4] \times 100}{[NH_4^{+}] + [NH_3]}](https://tex.z-dn.net/?f=%5C%25NH_4%5E%7B%2B%7D%20%3D%20%5Cfrac%7B%20%5BNH_4%5D%20%5Ctimes%20100%7D%7B%5BNH_4%5E%7B%2B%7D%5D%20%2B%20%5BNH_3%5D%7D)
= 
.....2
from equation 1 we have
{10^{8.5}}
plug this value in equation 2 we get

Total ammonia as N = 30 mg/lt
