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Rudiy27
2 years ago
14

Differentiate between velocity ratio and relative velocity in two points ??

Physics
1 answer:
stellarik [79]2 years ago
4 0
The difference between velocity and relative velocity is that velocity is measured with respect to a reference point which is relative to a different point. While relative velocity is measured in a frame where an object is either at rest or moving with respect to the absolute frame.
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A 195-gram, irregular piece of metal was dropped into a graduated cylinder containing 13.5 mL of water. The water level rose to
Naily [24]

Answer:

First Step:

Volume of metal sample= Final Volume - Initial Volume

Volume of metal= 37.4 mL - 33.0 mL = 4.40 mL

Second step:

Density= mass/ volume

Density= 7.101 g/ 4.40 mL = 1.61 g/mL

For part B, we are going in reverse.

First step, finding the volume of the metal=

Volume= mass/ Density

Volume= 7.101 g/ 2.7 g/mL= 2.63 mL

So, the water would have risen 2.63 mL when the aluminum sample would have been added.

Explanation:

4 0
3 years ago
One component of a magnetic field has a magnitude of 0.062 T and points along the x axis while the other component has a magnitu
adell [148]

Answer:

A) 62.37 x 10^(6) N

B) 59.86°

Explanation:

A) The magnitude of the force F1 due to the 0.062T magnetic field is;

F1 = |qo|(v)(Bx) Sin 90°

F1 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.062T = 53.94 x 10^(6) N

Also, the magnitude of the force F2 due to the 0.036T magnetic field is;

F2 = |qo|(v)(By) Sin 90°

F2 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.036T = 31.32 x 10^(6) N

Now, using Fleming's right hand rule, we will discover that the net force makes an angle with the x-axis. Let's call the angle θ. Since the forces will be at right angles to each other, then using Pythagoras theorem will get the resultant met force.

Thus;

F =√((F1)² + (F2)²) = √((53.94 x 10^(6))² + (31.32 x 10^(6))²)

= 62.37 x 10^(6) N

B) Since the forces are at right angles to each other, they are opposite and adjacent and since we know that tangent = opp/adj;

tan θ = F1/F2

tan θ = (53.94 x 10^(6)) / 31.32 x 10^(6) = 1.7222

Thus,θ = tan^(-1) 1.7222

θ = 59.86°

5 0
3 years ago
When an automobile moves with constant velocity, the power developed is used to overcome the frictional forces exerted by the ai
ollegr [7]

Answer:

P = F v

Where: P represent the power in Watts, F the force in Newtons and v the velocity in m/s

50 hp *\frac{746 W}{1 hp}= 37300 W

110 \frac{mi}{h} *\frac{1h}{3600 s} *\frac{1609.34 m}{1mi}= 49.17 \frac{m}{s}

And then we can find the force with the following formula:

F = \frac{P}{v}

And replacing we got:

F = \frac{37300 W}{49.17 m/s}= 758.527 N

And then the final answer for this case would be 758.52 N acting as the fricitional force.

Explanation:

For this case we can use the definition that the power can b expressed in terms of the force and the velocity like this:

P = F v

Where: P represent the power in Watts, F the force in Newtons and v the velocity in m/s

We can convert the power into Wtass like this:

50 hp *\frac{746 W}{1 hp}= 37300 W

110 \frac{mi}{h} *\frac{1h}{3600 s} *\frac{1609.34 m}{1mi}= 49.17 \frac{m}{s}

And then we can find the force with the following formula:

F = \frac{P}{v}

And replacing we got:

F = \frac{37300 W}{49.17 m/s}= 758.527 N

And then the final answer for this case would be 758.52 N acting as the fricitional force.

7 0
3 years ago
Suppose that you wish to construct a simple ac generator having 64 turns and an angular velocity of 377 radians/second (this is
Trava [24]

Answer:

\epsilon_{max} =12.064\ V

Explanation:

Given,

Number of turns, N = 64

angular velocity, ω = 377 rad/s

Magnetic field, B = 0.050 T

Area, a = 0.01 m²

maximum output voltage = ?

We know,

\epsilon_{max} = NBA\omega

\epsilon_{max} = 64\times 0.05\times 0.01\times 377

\epsilon_{max} =12.064\ V

The maximum output voltage is equal to 12.064 V.

3 0
3 years ago
A boy of weight 500 N has feet with a total area of 200 cm2
Vesna [10]
P = F (Force) / A (Area)

A should be in m^2, so 200 cm^2 = 0.02 m^2 (200:10000)

p = 500/0.02 = 25000 N/m^2
5 0
3 years ago
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