Answer:
First Step:
Volume of metal sample= Final Volume - Initial Volume
Volume of metal= 37.4 mL - 33.0 mL = 4.40 mL
Second step:
Density= mass/ volume
Density= 7.101 g/ 4.40 mL = 1.61 g/mL
For part B, we are going in reverse.
First step, finding the volume of the metal=
Volume= mass/ Density
Volume= 7.101 g/ 2.7 g/mL= 2.63 mL
So, the water would have risen 2.63 mL when the aluminum sample would have been added.
Explanation:
Answer:
A) 62.37 x 10^(6) N
B) 59.86°
Explanation:
A) The magnitude of the force F1 due to the 0.062T magnetic field is;
F1 = |qo|(v)(Bx) Sin 90°
F1 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.062T = 53.94 x 10^(6) N
Also, the magnitude of the force F2 due to the 0.036T magnetic field is;
F2 = |qo|(v)(By) Sin 90°
F2 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.036T = 31.32 x 10^(6) N
Now, using Fleming's right hand rule, we will discover that the net force makes an angle with the x-axis. Let's call the angle θ. Since the forces will be at right angles to each other, then using Pythagoras theorem will get the resultant met force.
Thus;
F =√((F1)² + (F2)²) = √((53.94 x 10^(6))² + (31.32 x 10^(6))²)
= 62.37 x 10^(6) N
B) Since the forces are at right angles to each other, they are opposite and adjacent and since we know that tangent = opp/adj;
tan θ = F1/F2
tan θ = (53.94 x 10^(6)) / 31.32 x 10^(6) = 1.7222
Thus,θ = tan^(-1) 1.7222
θ = 59.86°
Answer:

Where: P represent the power in Watts, F the force in Newtons and v the velocity in m/s


And then we can find the force with the following formula:

And replacing we got:

And then the final answer for this case would be 758.52 N acting as the fricitional force.
Explanation:
For this case we can use the definition that the power can b expressed in terms of the force and the velocity like this:

Where: P represent the power in Watts, F the force in Newtons and v the velocity in m/s
We can convert the power into Wtass like this:


And then we can find the force with the following formula:

And replacing we got:

And then the final answer for this case would be 758.52 N acting as the fricitional force.
Answer:

Explanation:
Given,
Number of turns, N = 64
angular velocity, ω = 377 rad/s
Magnetic field, B = 0.050 T
Area, a = 0.01 m²
maximum output voltage = ?
We know,



The maximum output voltage is equal to 12.064 V.
P = F (Force) / A (Area)
A should be in m^2, so 200 cm^2 = 0.02 m^2 (200:10000)
p = 500/0.02 = 25000 N/m^2