Answer:
No. 67
Peter Street
12th Road
Chennai
24th June 201_
Dear Amrish
I have come to know that since your school has closed for the Autumn Break you have plenty of free time at your disposal at the moment. I would like to tell you that even I am having holidays now.
It has been a long time since we have spent some time together. If you are free, I would welcome to have your company this weekend. Why don’t you come over to my house and spend a day or so with me?
I am anxiously waiting for your reply.
Yours affectionately
your name
Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A
The vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.
The forces exerted on an object can be resolved into <em>horizontal</em> and <em>vertical components.</em>
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The horizontal components of the forces on an object being pulled include the following;
- The frictional force on the object; which tends to reduce the motion,
- force dragging the object forward
- if the object is inclined to an angle, the horizontal component of the weight
This horizontal force is written as;
The vertical component of the force on the object include the following;
- the weight of the object acting downwards
- the pull of air on the object acting upwards
The vertical force on the object is written as;
Thus, the vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.
Learn more here: brainly.com/question/2000189
The volume of any rectangular solid, including a cube, is calculated mathematically as V = l × w × h
<h3>How to find a cross-sectional area?</h3>
In a given calculation, if you are given the:
To find this, you would have to use the area of its base which is:
Length * Width * Height.
Furthermore, if the cross-section is parallel, then you would have to solve it thus:
Length * Width which is the area of the section from top to bottom.
Although your question is incomplete, the general idea of how to find the cross-sectional area of the volume of any rectangular solid.
Read more about cross-sectional area here:
brainly.com/question/10429397
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