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worty [1.4K]
3 years ago
7

1/4 to 1/2

Mathematics
1 answer:
erastovalidia [21]3 years ago
7 0

Given:

\dfrac{1}{4}\text{ to }\dfrac{1}{2}

To find:

The percent of change, round to the nearest 10th of a percent.

Solution:

We have,

Initial value = \dfrac{1}{4}

New value = \dfrac{1}{2}

We know that, the percentage change is

\%\text{ change}=\dfrac{\text{New value - Initial value}}{\text{Initial value}}\times 100

Putting the given values, we get

\%\text{ change}=\dfrac{\dfrac{1}{2}-\dfrac{1}{4}}{\dfrac{1}{4}}\times 100

\%\text{ change}=\dfrac{\dfrac{2-1}{4}}{\dfrac{1}{4}}\times 100

\%\text{ change}=\dfrac{\dfrac{1}{4}}{\dfrac{1}{4}}\times 100

\%\text{ change}=1\times 100

\%\text{ change}=100\%

Here, the % change is positive, it represents the percent increase.

Therefore, the percent of change is 100% of increase.

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