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worty [1.4K]
3 years ago
7

1/4 to 1/2

Mathematics
1 answer:
erastovalidia [21]3 years ago
7 0

Given:

\dfrac{1}{4}\text{ to }\dfrac{1}{2}

To find:

The percent of change, round to the nearest 10th of a percent.

Solution:

We have,

Initial value = \dfrac{1}{4}

New value = \dfrac{1}{2}

We know that, the percentage change is

\%\text{ change}=\dfrac{\text{New value - Initial value}}{\text{Initial value}}\times 100

Putting the given values, we get

\%\text{ change}=\dfrac{\dfrac{1}{2}-\dfrac{1}{4}}{\dfrac{1}{4}}\times 100

\%\text{ change}=\dfrac{\dfrac{2-1}{4}}{\dfrac{1}{4}}\times 100

\%\text{ change}=\dfrac{\dfrac{1}{4}}{\dfrac{1}{4}}\times 100

\%\text{ change}=1\times 100

\%\text{ change}=100\%

Here, the % change is positive, it represents the percent increase.

Therefore, the percent of change is 100% of increase.

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The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and
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The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

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Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of <u>proportionality</u>, i.e., if divided, the result is a constant.

For the first load:

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For the similar beam:

\frac{8.7^{2}}{L}1300=1300

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

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