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o-na [289]
3 years ago
9

Which bonds form in the reaction shown in the diagram? 2 2H, + 0 H-H O=0 H-H → 2H 0 H-0-H H-OH A. The bonds between the two hydr

ogen atoms and between the two oxygen atoms B. The bonds between the two hydrogen atoms C. The bonds between the oxygen and hydrogen atoms D. The bonds between the two oxygen atoms​

Chemistry
2 answers:
Nadya [2.5K]3 years ago
8 0

Answer:

C

Explanation:

The bonds between H--H and O==O break and form bonds between O and H

H--O--H

m_a_m_a [10]3 years ago
5 0

Answer:

c brooo

Explanation:

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Which compound is composed of oppositely charged ions? A. SCl2 B. OF2 C. PH3 D. Li2O
netineya [11]

Answer:

D.

Explanation:

If a compound is composed of oppositely charged ions, it has to be formed by metal and non-metal.

Li2O

Li - metal

O - non-metal

7 0
2 years ago
Suppose a current of is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for s
WARRIOR [948]

The given question is incomplete. The complete question is:

Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.

Answer:   0.0484 g

Explanation:

Q=I\times t

where Q= quantity of electricity in coloumbs

I = current in amperes = 0.920 A

t= time in seconds = 47.0 sec

Q=0.920A\times 47.0s=43.24C

AgNO_3\rightarrow Ag^++NO_3^-

Ag^++e^-\rightarrow Ag

96500 Coloumb of electricity electrolyzes 1 mole of Ag

43.24 C of electricity deposits =\frac{1}{96500}\times 43.24=0.00045moles of Ag

\text{ mass of Ag}={\text{no of moles}\times {\text{Molar mass}}=0.00045mol\times 108g=0.0484g

Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g

6 0
2 years ago
_Cl2 + __KI → __KCI + __12
Snowcat [4.5K]

Answer:

Cl2 +2Kl ----->2KCL +I2

Explanation:

_Cl2 + __KI → __KCI + __I2

Cl2 +2Kl ----->2KCL +I2

8 0
2 years ago
Does ecstasy drug effect how long you live?
const2013 [10]

Answer:

yes it gives some bad effect

Explanation:

6 0
2 years ago
For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox
ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: m_{N2}=10.682 g N_2

2) Limiting reagent: NO

3) Ammount of excess reagent: m_{N2}=4.274 g

Explanation:

<u>The reaction </u>

2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)

Moles of nitrogen monoxide

Molecular weight: M_{NO}=30 g/mol

n_{NO}=\frac{m_{NO}}{M_{NO}}

n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol

Moles of hydrogen

Molecular weight: M_{H2}=2 g/mol

n_{H2}=\frac{m_{H2}}{M_{H2}}

n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}

m_{N2}=10.682 g N_2

2) <u>Limiting reagent</u>: NO

3) <u>Ammount of excess reagent</u>:

m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}

m_{N2}=4.274 g

8 0
3 years ago
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