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nevsk [136]
3 years ago
5

Help me with 5 daily life situations to find the resultant force.

Physics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

Ok! :)

Explanation:

"A resultant force is the single force and associated torque obtained by combining a system of forces and torques acting on a rigid body. The defining feature of a resultant force, or resultant force-torque, is that it has the same effect on the rigid body as the original system of forces."

Also known as net force.

Ball pushed one was with 5 N right, other way 1 N left.

Net force = 4 N to right.

Box thrown 10 up, pushed 20 down. Net force = 10 down.

Can't think of 3 more...   :)

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H_2O \rightarrow H_2 +\frac {1}{2}O_2

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6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2

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6 0
3 years ago
Two equally charged, 2.098 g spheres are placed with 3.338 cm between their centers. When released, each begins to accelerate at
photoshop1234 [79]

Answer:

2.64\times 10^{-7} C

Explanation:

There are two spheres name 1 and 2 and they posses the same charge, which is +q.

And they have equal mass which is 2.098 g.

The distance between these two spheres is, r=3.338 cm.

And the acceleration of each sphere is, a=269.429 m/s^{2}.

Now the coulumbian force experience by 1 sphere due to 2 sphere,

F_{21} =\frac{q^{2} }{4\pi\epsilon_{0} r^{2}  }.

And also the newton force will occur due to this force,

F_{21}=ma.

Now equate the above two values of force will get,

\frac{q^{2} }{4\pi\epsilon_{0} r^{2}  } =ma

Further solve this,

q^{2}=ma4\pi  \epsilon_{0} r^{2}.

Substitute all the known variables in above equation,

q^{2}=(2.098\times 10^{-3} )(269.429)(4(3.14))(8.85\times 10^{-12})(3.338\times 10^{-2}).

q=2.64\times 10^{-7} C.

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3 years ago
the density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas
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The type of relationship between atmospheric density and altitude is therefore inverse relationship. This means an increase in either will decrease the other factor. Density is mass per unit volume, it is difficult to calculate with only altitude 1,291 kilometers given. Else, we could also use temperature and pressure to solve density but they are not provided.
5 0
3 years ago
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6) What force should be applied to compress a spring
valina [46]

Answer:

26.6N

Explanation:

Using Hooke’s law

F = kx

Where F = force

K = spring constant

x = displacement

From the question

F= ?

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x = 0.19m

Therefore,

F = 140 x 0.19

= 26.6N

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2 years ago
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Answer:

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