B.if it is, determine the number of p,n,and e’s.
Respuesta:
90.0 %
Explicación:
Paso 1: Escribir la ecuación química balanceada
N₂ + 3 H₂ ⇒ 2 NH₃
Paso 2: Calcular el rendimiento teórico de NH₃ a partir de 140 g de N₂
En la ecuación balanceada, participan de N₂: 1 mol × 28.01 g/mol = 28.01 g y de NH₃: 2 mol × 17.03 g/mol = 34.06 g.
140 g N₂ × 34.06 g NH₃ /28.01 g N₂ = 170 g NH₃
Paso 3: Calcular el rendimiento porcentual de NH₃
El rendimiento experimental de NH₃ es 153 g. Podemos calcular el rendimiento porcentual usando la siguiente fórmula.
R% = rendimiento experimental / rendimiento teórico × 100%
R% = 153 g / 170 g × 100% = 90.0 %
Answer:
hello since your question is old i shall use it for points if you don't mind✨
The change in enthalpy associated with the change in the water’s temperature is 1254 J.
<h3>What is specific heat?</h3>
The amount of heat required to increase the temperature of one gram of a substance by one Celsius degree is known as specific heat.
Enthalpy change will be calculated as:
ΔH = -cmΔT, where
m = mass of water = 50g
c = specific heat of water = 4.18J/g°C
ΔT = change in temperature = 28 - 22 = 6 °C
On putting values in the above equation, we get
ΔH = -(4.18)(50)(6) = -1254 J
Hence change in enthalpy of the reaction is -1254 J.
To know more about enthalpy change, visit the below link:
brainly.com/question/11628413
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