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grigory [225]
3 years ago
5

Infrared (IR) and Nuclear Magnetic Resonance (NMR) are two spectroscopic techniques you've encountered in organic chemistry I, C

HM2210. In organic chemistry laboratory, IR and NMR are common tools used to characterize a given product. Consider what you learned in CHM22110, and select the concepts that you feel confident about: Group of answer choices Assigning 1H NMR signals to a given molecule The theory behind NMR Identify splitting patterns I do not recall/understand much about NMR correlate the intensity of a 1H NMR signal to the number of protons The theory behind IR I do not recall/understand much about IR Assigning 13C NMR signals to a given molecule Identify functional groups based on IR absorptions Understanding (de)sheilding Deduce the structure of an unknown given its molecular formula, IR and NMR spectra
Chemistry
1 answer:
zalisa [80]3 years ago
8 0

Answer:

The solution to this question can be defined as follows:

Explanation:

Please find the attached file for the solution:

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7. A cyclist starting from rest accelerates at a rate of 6 m/s until she reaches 30 m/s. How long
Hunter-Best [27]

Answer:

Explanation:

The given values are:

a= 6m/s²

u= 0 m/s

v = 30 m/s

t= ?

The formula is :

a=\frac{v-u}{t}

thus,

t=\frac{v-u}{a}\\t=\frac{30-0}{6}\\t= 5 seconds

4 0
3 years ago
Which term best describes the relationship between D-Mannose and L-Mannose?
frosja888 [35]

Answer: The correct answer is C.

Explanation: Hope this helps plz mark brainliest.

5 0
3 years ago
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What is the mass of 15100 mL of oxygen gas at STP?
adell [148]

Answer:

02 has a mass of 1.78 g.

Explanation:

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2 years ago
How does changing temperature affect the solubility of gases in liquids?
Allisa [31]

Answer:

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8 0
3 years ago
cooling a sample of matter from 70°c to 10°c at constant pressure causes its volume to decrease from 873.6 to 712.6 cm3. classif
jek_recluse [69]

Explanation:

Expression for the coefficient of thermal expansion is as follows.

           \alpha = \frac{1}{V}(\frac{\Delta V}{\Delta T})

where,   V = initial volume

          \Delta V = Final volume - initial volume

                      = (712.6 - 873.6) cm^{3}

                      = -161 cm^{3}

Now, we will calculate the change in temperature as follows.

          \Delta T = Final temperature - Initial temperature

                       = (10 + 273) K - (70 + 273) K

                       = 283 K - 343 K

                       = -60 K

Substituting these values into the equation as follows.

     \alpha = \frac{1}{873.6} \times (\frac{161}{60}) K^{-1}

                 = 0.00307 K^{-1}

It is known that for non-ideal gases the value of alpha is 0.366% which is 0.00366 per Kelvin. As it is close to our result, hence the given sample of gas is a non-ideal gas.

3 0
4 years ago
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