<span>rms = (3RT/M)^1/2
Therefore, the rms of CO is:
rms(CO) = [(3)(8.3145 J/mol*K)(320 K)/(0.028 kg/mol)]^1/2
rms = [2.65x10^5 m^2/s^2]^1/2
rms = 533.9181 m/s</span>
Answer: 0.94 V
Explanation:
For the given chemical reaction :

Using Nernst equation :
where,
F = Faraday constant = 96500 C
R = gas constant = 8.314 J/mol.K
T = room temperature =
n = number of electrons in oxidation-reduction reaction = 2
= standard electrode potential of the cell = +1.10 V
= emf of the cell = ?
Now put all the given values in the above equation, we get:
The cell potential for this reaction is 0.94 V
Answer:
Berilium is located in period 2 group2
Explanation:
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1- First we will get the value of POH from:
PH + POH = 14
and we have PH = 12.01
∴ POH = 14 - 12.01 = 1.99
2- Then we need to get the concentration of OH:
when POH = -㏒[OH]
1.99 = -㏒[OH]
∴[OH] = 0.01 M
now we have the concentration at Equ by subtracting from the initial concentration of OH = 0.24 M
∴ [OH] = 0.24 - 0.01 = 0.23 M
∴ Kb = (0.01)^2 / 0.22977 M
∴ Kb value = 4.4 x 10^-4